Q = mass x specific heat x delta T 343 = 55.0 x specific heat ( 86.0 - 19.0 ) 343 = 3685 x specific heat specific heat = 0.0931 cal /g°C
Shoutout to @hihi67
Your answer is: 0.0931 cal/g degrees C
Have an amazing day and stay hopeful!
Answer:
you know what i really dont know but imagine if they were huge
Explanation:
I think the answer would be A ! Hope this helps
-OH is elctron donating -C=-N is electron withdrawing -O-CO-CH3 is electron withdrawing -N(CH3)2 is electron donating -C(CH3)3 is electron donating -CO-O-CH3 is electron withdrawing -CH(CH3)2 is electron donating -NO2 is electrong withdrawing -CH2
