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choli [55]
3 years ago
6

How big are the bighest ocean waves at Mavericks

Chemistry
1 answer:
Triss [41]3 years ago
6 0

The biggest ocean wave that was ever recorded was 70+ feet tall.

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Can yall assist me with this lab? It is really screwing me up... No spam!! the only part that I need is the last page. I will ma
kenny6666 [7]

Answer:

What do you need help with?!

Explanation:

5 0
2 years ago
What volume of 0.25 M HCl would be needed to neutralize 45 mL of 0.12 M solution of Mg(OH)₂
dalvyx [7]

Answer:

0.38dm³

Explanation:

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4 0
3 years ago
Geologists divide Earth’s long history into smaller units that make up the geologic time scale.
aleksandrvk [35]

False

Explanation:

The geologic time scale which simplifies earth's long history is broad division of deep time. It consists of a large and small divisions.

  • The geologic time scale is divided into large broad categories; called eons, eras, period and epoch.
  • The scale is merges absolute dating of events that has happened in geologic past and their relative ages.
  • Broad categories on the scale are further simplified into smaller units.
  • Relative age puts events in the order of their appearance using a couple of geologic principles.

Learn more;

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8 0
3 years ago
The reaction of hydrogen and iodine to produce hydrogen iodide has a Kc of 54.3 at 703 K. Given the initial concentrations of H2
pentagon [3]

Answer:

[HI] = 0.7126 M

Explanation:

Step 1: Data given

Kc = 54.3

Temperature = 703 K

Initial concentration of H2 and I2 = 0.453 M

Step 2: the balanced equation

H2 + I2 ⇆ 2HI

Step 3: The initial concentration

[H2] = 0.453 M

[I2] = 0.453 M

[HI] = 0 M

Step 4: The concentration at equilibrium

[H2] = 0.453 - X

[I2] = 0.453 - X

[HI] = 2X

Step 5: Calculate Kc

Kc = [Hi]² / [H2][I2]

54.3 = 4x² / (0.453 - X(0.453-X)

X = 0.3563

[H2] = 0.453 - 0.3563 = 0.0967 M

[I2] = 0.453 - 0.3563 = 0.0967 M

[HI] = 2X = 2*0.3563 = 0.7126 M

3 0
3 years ago
20 mL of 80°C water is mixed with 20 mL of 0°C water in a perfect calorimeter. What is the final temperature?
dedylja [7]
To calculate for the final temperature, we need to remember that the heat rejected should be equal to the absorbed by the other system. We calculate as follows:

Q1 = Q2
(mCΔT)1 = (mCΔT)2

We can cancel m assuming the two systems are equal in mass. Also, we cancel C since they are the same system. This leaves us,

 (ΔT)1 = (ΔT)2
(T - 80) = (0 - T)
T = 40°C
8 0
3 years ago
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