What is the pH of a 40.0 40.0 mL solution that is 0.11 0.11 M in CN − CN− and 0.21 0.21 M in HCN HCN ? The K a Ka for HCN is 4.9
× 10 − 9
1 answer:
Answer:
pH=8.03
Explanation:
From the Henderson-Hasselbalch equation:
we know that
pH = pKa + log (base / acid)
plugging the values from the question we can write
pH = 8.31 + log (0.11 / 0.21)
pH = 8.31-0.280
pH=8.03
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