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alisha [4.7K]
3 years ago
14

Which graph would help solve the equation 5log(x+3)=5

Mathematics
2 answers:
olga_2 [115]3 years ago
8 0
<span><span>5log(x+3)=5</span><span>5log(x+3)=5</span></span>Simplify <span><span>5log(x+3)</span><span>5log(x+3)</span></span> by moving 55 inside the logarithm.<span><span>log<span>(<span>(x+3)5</span>)</span></span><span>log<span>(<span>(x+3)5</span>)</span></span></span>Simplify the right side of the equation.55Graph each side of the equation. The solution is the x-value of the point of intersection.<span>x=7

</span>
Ivenika [448]3 years ago
8 0

Answer: B. The Second Graph

-nyfb

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Tabitha wants to hang a painting in a gallery. The painting and frame must have an area of 58 square feet. The painting is 7 fee
lianna [129]
The quadratic equation would be;
x2+15x-2=0

Working:
Assuming the area around the painting i.e the frame, has a uniform thickness, then;
Length of painting and frame = 8+x
Breadth of painting and frame= 7+x

The area from above step gives;
 A= LxW
A= (8+x)(7+x)
On expanding, 56+8x+7x+x2
On simplifying,
56+15x+x2. This should be equal to 58.
58=x2+15x+56
Taking 58 to the other side,
x2+15x-2=0

7 0
4 years ago
For what values of x is f(x) = square root of x-4 equal to 4?
zaharov [31]

Answer:

x = 20

Step-by-step explanation:

given f(x) = \sqrt{x-4}, we have to solve

\sqrt{x-4} = 4

Square both sides

(\sqrt{x-4})² = 4²

x - 4 = 16 ( add 4 to both sides )

x = 20

As a check

\sqrt{20-4} = \sqrt{16} = 4 ← correct




3 0
4 years ago
8x+112x+392 factor perfect squares
Elis [28]

1

2

0

x

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120x+392

Step-by-step explanation:

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3 years ago
What is the range of f(x)=4^x?
NISA [10]
I really don’t know do you have a picture that you can show me
3 0
3 years ago
 I am so confused on functions! Please help! 
Gekata [30.6K]
Functions are basically another way of expressing a way to get y or x or anything (mostly used for graphs) You will see functions like <em>f(x)=</em> <em>23y-5 </em>(that was made up). Basically the number in the parenthesis in front of the f is what you're finding. So the equation after the equal sign is how to find whatever is being found. So in this case, finding x can be pretty easy. By the way, when graphing this you have x as the run and y as the rise. <em />
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