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Bumek [7]
3 years ago
12

The box plots show the high temperatures in january and march for denmark in degrees fahrenheit. box plots titled average daily

temperatures in denver in march and january with horizontal axis labeled temperature in degrees fahrenheit ranges from 45 to 80. march box plot with minimum approximately at 55 and maximum approximately at 75, its interquartile range is approximately between 60 and 70, and the median is between 60 and 65. january box plot is with minimum approximately 55 and maximum approximately at 70, its interquartile range is approximately between 57 and 65, and its median is approximately between 60 and 65. which can you tell about the mean temperatures for these two months?
Mathematics
2 answers:
spin [16.1K]3 years ago
8 0
From the information, the mean temperature for January is most likely lower than the mean temperature for March.

There are a couple of clues to this assumption. First, the max temp is lower for January. Second, the interquartile range is lower in March. With both of these factors, it is safe to assume the mean is lower.
Wittaler [7]3 years ago
7 0
<span>The low median for January pulls the mean temperature below March's mean temperature. If just count the mean of both months it smake sense the most.</span>
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A rectangle measures 2 inches by 5 inches. If the length of each side doubles, what will be the area of the new rectangle
fenix001 [56]

Answer:

<h3>40 inches squared</h3>

Step-by-step explanation:

2+2=4

5+5=10

10x4=40

4 0
3 years ago
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Paula finished the race at 2:14 p.m Beatrice finished the race 22 minutes earlier what time did Beatrice finish the race a 1:54
ella [17]

Answer:  d: 1:52pm

Step-by-step explanation:  Since Beatrice finished 22 minutes earlier, we subtract 22 minutes from 2:14. 2:14 - 14 is 2:00. 22-14 is 8. 2:00 - 8 is 1:52.

8 0
2 years ago
Keith's height and his nephews height was at a ratio of 15:7 then, keith's Height increased by 16% and his nephews height double
Vikentia [17]

Answer:

311.6 cm

Step-by-step explanation:

To solve this problem, let's call:

k = Keith's height

n = nephew's height

Since the ratio is 15:7, we have

\frac{k}{n}=\frac{15}{7}\\k=\frac{15}{7}n (1)

Then, Keith's height is increased by 16%, so the new height of Keith is

k'=k+0.16 = 1.16k  (2)

While the nephew's height is doubled:

n'=2n (3)

We also know that Keith is now 34 cm taller than his nephew, so

k'=n'+34 (4)

Substituting (2) and (3) into (4), we get

1.16k=2n+34

And substituting (1),

1.16\cdot \frac{15}{7}n=2n+34

Solving for n,

2.49n=2n+34\\\\0.49n=34\\n=\frac{34}{0.49}=69.4

So the current height of the nephew is:

n'=2n=2(69.4)=138.8 cm

While Keith's current height is

k'=138.8+34=172.8 cm

So their total current height is

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8 0
4 years ago
A total of 60% of the customers of a fast food chain order a hamburger, French fries, and a drink. If a random sample of 15 cash
Ne4ueva [31]

Answer:

C. 0.403

Step-by-step explanation:

Binomial distribution has two parameter n and p. Here, n=15 and p=0.60.

We have to find the probability of 10 or more will show that the hamburger, French fries and a drink were ordered. P(X≥10)=?

The binomial probability distribution function for random variable X  is

P(X=x)=nCxp^{x} q^{n-x}

where q=1-p=1-0.6=0.4,n=15 and p=0.6.

P(X≥10)=P(X=10)+P(X=11)+P(X=12)+P(X=13)+P(X=14)+P(X=15)

P(X=10)=15C10(0.6^{10})( 0.4^{5}) =0.185938

P(X=11)=15C11(0.6^{11}) (0.4^{4}) =0.126776

P(X=12)=15C12(0.6^{12}) (0.4^{3}) =0.063388

P(X=13)=15C13(0.6^{13}) (0.4^{2}) =0.021942

P(X=14)=15C14(0.6^{14}) (0.4^{1}) =0.004702

P(X=15)=15C15(0.6^{15}) (0.4^{0}) =0.000470

P(X≥10)= 0.185938 +0.126776 +0.063388 +0.021942 +0.004702 +0.000470

P(X≥10)=0.403216

So, the probability of 10 or more will show that the hamburger, French fries and a drink were ordered is 0.403.

8 0
3 years ago
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nikitadnepr [17]
In this question the answer is C

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4 0
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