3 years ago

Which equation is equivalent to x^2 + 2x – 3 = 0?

Mathematics

2 answers:

Ksivusya [100]3 years ago

6 0

I believe your answer should be: (A) (x+1)^2=4

andrey2020 [161]3 years ago

5 0

Answer:

a) is the correct answer

Step-by-step explanation:

When we expand a) we get

x^2+2x+1=4

Subtracting 4 on both sides we get x^2+2x+1-4=0

x^2+2x-3=0

You might be interested in

231 km 811 m + 485 km 829 m

Eva8 [605]

231+811+485+829=2356km

6 0

3 years ago

Read 2 more answers

Given the linear equation r=-2.5 t and t can only be a negative number, what quandrant will the r coordinate be located?

Citrus2011 [14]

Answer:

quadrant 4 i think

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Austins movie collections contains 9 movies, including 3 comedies. What is the probability that a randomly selected movie will b

storchak [24]

Answer:

There is a 3 in 9 chance

Step-by-step explanation:

4 0

3 years ago

In one season, Moses made 4 times as many goals as Kyle. Together, they made 15 goals. How many goals did Moses make and how man

Likurg_2 [28]

4x+x= 15 5x=15 x=3 Moses made 12 goals and Kyle made 3

4 0

4 years ago

From a practice assignment:<br>solve the following differential equation given initial conditions

hodyreva [135]

If $y' = e^y \sin(x)$ and $y(-\pi)=0$ , separate variables in the differential equation to get

$e^{-y} \, dy = \sin(x) \, dx$

Integrate both sides:

$\displaystyle \int e^{-y} \, dy = \int \sin(x) \, dx \implies -e^{-y} = -\cos(x) + C$

Use the initial condition to solve for $C$ :

$-e^{-0} = -\cos(-\pi) + C \implies -1 = 1 + C \implies C = -2$

Then the particular solution to the initial value problem is

$-e^{-y} = -\cos(x) - 2 \implies e^{-y} = \cos(x) + 2$

(A)

4 0

2 years ago