If we let
x as the distance traveled by the boat
y as the distance between the boat and the lighthouse.
Then, we have:
tan 18°33' = 200 / (x + y)
and
tan 51°33' = 200 / y
Solving for y in the second equation:
y = 200 / tan 51°33'
Rearranging the first equation and substituting y
x = 200 / tan 18°33' - 200 / tan 55°33'
x = 458.81 ft
Therefore, the boat traveled 458.81 ft before it stopped.
<span>If you know the Linear pair Theorem, the converse can be easily obtained by switching the condition and the conclusion.
For example,
If it is raining, then the outside is wet.
Converse: If the outside is wet, then it is raining. (It is not always true.)</span>
-6(2x - 4) = -6*(2x) -6*(-4) = -12x + 24
-(12x - 6) + 18 = -12x + 6 + 18 = -12x + 24
-3(4x - 3) + 15 = -3*(4x) -3*(-3) + 15 = -12x + 9 + 24 = -12x + 24
-4(3x + 6)
= -4*(3x) -4*(6) = -12x -24
All the expressions gave the same answer as -12x + 24, except for the last expression.
So, -4(3x + 6)
is not equivalent to the others.
AREA OF A RECTANGLE IS 42 UNITS
Rectangle: Triangle:
A = L * W A = hb / 2
A = (x-8) * 6 A = (7(x-3)) / 2
A = 6x - 48 A = (7x - 21) / 2
Since the problem states that both rectangle and triangle have the same area.Then:
6x - 48 = (7x - 21) / 2
1) Eliminate the denominator 2 by multiplying both sides by 2.
2 * (6x - 48) = 2 * ((7x - 21) / 2)
12 x - 96 = 7x - 21
Find x. Transfer like numbers and change their signs.
12x - 7x = 96 - 21
5x = 75
5x / 5 = 75 / 5
x = 15
Substitute x by its value:
Rectangle: Triangle
A = (x-8) * 6 - A = (7(x-3)) / 2 Areas of both Rectangle
A = (15 -8 ) * 6 A = (7(15-3)) / 2 and Triangle is the same.
A = 7 * 6 A = (7 * 12) / 2
A = 42 units A = 84 / 2
A = 42 units
