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3 years ago

Help plz?????????????????

Mathematics

2 answers:

arlik [135]3 years ago

8 0

Answer:

Step-by-step explanation:

40% of 11 = 0.40*11 = 4.40

Cost of larger pizza = 11.00 + 4.40 = $ 15.40

SCORPION-xisa [38]3 years ago

6 0

Answer:

$11.40

Step-by-step explanation:

40%=.40

11.00+0.40

=$11.40

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What is the inverse of the function below? f(x)= x/4 -2

user100 [1]

$f(x)=\dfrac{x}{4}-2\to y=\dfrac{x}{4}-2\\\\\text{Interchange the y and the x}\\\\x=\dfrac{y}{4}-2\\\\\text{Solve for y}\\\\\dfrac{y}{4}-2=x\qquad|+2\\\\\dfrac{y}{4}=x+2\qquad|\cdot4\\\\y=4(x+2)$

$Answer:\ C.\ f^{-1}(x)=4(x+2)$

3 0

3 years ago

Pls help with 29..tank you

trapecia [35]

Answer:

See below

Step-by-step explanation:

Let the 2 roots be A and A^2.

Then A^3 = c/a and A + A^2 = -b/a.

Using the identity a^3 b^3 = (a + b)^3 - 3ab^2 - 3a^2b:-

A^3 + (A^2)^3 = ( A + A^2)^3 - 3 A.A^4 - 3 A^2. A^2

= (A + A^2)^3 - 3A*3( A + A^2)

Substituting:-

c/a + c^2/a^2 = (-b/a)^3 - 3 (c/a)(-b/a)

Multiply through by a^3:-

a^2c + ac^2 = -b^3 + 3abc

Factoring:-

ac(a + c) = 3abc - b^3

This is not the formula required in the question but let's see if the formula in the question reduces to this. If it does we have completed the proof.

a(c - b)^3 = a(c^3 - 3c^2b + 3cb^2 - b^3) = ac^3 - 3ac^2b + 3acb^2 - ab^3

c(a - b)^3 = c(a^3 - 3a^2b + 3ab^2 - b^3) = ca^3 - 3a^2bc + 3acb^2 - cb^3.

These are equal so we have

ca^3 - 3a^2bc + 3acb^2 - cb^3 = ac^3 - 3abc^2 + 3acb^2 - ab^3

The 3acb^2 cancel out so we have:-

a^3c - ac^3 = 3a^2bc - 3abc^2 + b^3c - ab^3

ac(a^2 - c^2) = 3abc( a - c) + b^3(c - a)

ac(a + c)(a -c) = 3abc(a - c) - b^3 (a - c)

Divide through by (a - c):-

ac(a + c) = 3abc - b^3 , which is the result we got earlier.

This completes the proof.

3 0

3 years ago

Read 2 more answers

Point G is on line segment FH. Given FH = 5x + 2, GH = 5x – 9, and

Anni [7]

Answer:

Step-by-step explanation:

6 0

3 years ago

53% of what number is 384? <br> i got 724.52 how do i round it to the hundredths place?

aleksandr82 [10.1K]

Answer:

thats right.

Step-by-step explanation:

the first place after the decimal is tenths, second, hundredths, third thousands, and so on

6 0

3 years ago

the graph shows the speed of a vehicle during the final 50 seconds of a journey at the start of the 50 seconds the speed is k me

Simora [160]

Answer:

a) 27 m/s

b) 30 m/s

c) i) 3

ii) Deceleration

Step-by-step explanation:

The question is not complete, the correct question is given as:

The graph shows information about the speed of a vehicle during the final 50 seconds of a journey. At the start of the 50 seconds the speed is k metres per second. The distance travelled during the 50 seconds is 1.35 kilometres.

(a) Work out the average speed of the vehicle during the 50 seconds

(b) Work out the value of k.

(ii) Describe what this gradient represents

Answer:

The graph is attached. The total time = 50 seconds, total distance = 1.35 km = 1350 m

a) The average speed is the ratio of the total distance traveled to the total time taken to cover this distance. The average speed is given by the formula:

$Average \ speed=\frac{total\ distance}{total\ time}\\ Substituting: \\ Average \ speed=\frac{1350\ m}{50\ s} = 27\ m/s$

b) From the graph, the total distance covered is the area of the graph. The graph is made up of a rectangle and triangle, the area of the graph is equal to the sum of area of rectangle and area of triangle.

$Total \ distance=Total\ area=Area\ of \ rectangle+Area\ of \ triangle\\Total \ distance=(length *breadth)+\frac{1}{2}base*height\\1350 \ m=(40*k)+0.5*10*k\\1350=40k+5k\\45k=1350\\k=1350/45\\k=30\ m/s$ c) i) The gradient in the last 10 seconds is the ratio of change in speed to change in time

$Gradient=\frac{change\ in\ speed }{change\ in\ time}=\frac{0-k}{50-40} \\ bt \ k=30\\Gradient=\frac{0-30}{50-40}= \frac{-30}{10} =-3$

ii) Since the gradient is negative it means it is deceleration. That is in the in the last 10 seconds the vehicle decelerates at a rate of 3 m/s²

6 0

3 years ago