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olasank [31]
3 years ago
6

Rewrite each fraction with a denominator of 10 7/2=? 3/5=?​

Mathematics
1 answer:
motikmotik3 years ago
5 0
The answer is 35/10 and 6/10
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Active
Ber [7]

Answer:

The expressions for the payment made to Mary are,

(Monday) 90 = 15m + b

(Tuesday) 62 = 8m + b

where m and b are the fee per student and the base fee, respectively. Solving for m and b, the values are 4 and 30.

The equation that represents Mary's earning is

y = 4x + 30

For 20 students,

y = 4(20) + 30 = 110

For Lisa's earnings,

y = 8x + 15

Substituting 20,

y =8(20) + 15 = 175

Thus, Lisa would earn more than Mary by $65.

(Btw this is not my work, I got it from someone else on brainly and wanted to help lol)

7 0
3 years ago
Combine like terms to find the expression
Scrat [10]

Answer:

2.1

Step-by-step explanation:

6 0
3 years ago
Y = -3x-2 Slope intercept form
lana66690 [7]

Answer:The equation of any straight line, called a linear equation, can be written as: y = mx + b, where m is the slope of the line and b is the y-intercept. The y-intercept of this line is the value of y at the point where the line crosses the y axis.

Step-by-step explanation:

4 0
3 years ago
Community Gym charges a $50 membership fee and a $70 monthly fee. Workout Gym charges a $190
zepelin [54]

Answer:

14 month

Step-by-step explanation:

Lets create equations for these two gyms. I believe this is an algebra 1 problem.

Community Gym: y=70x+50

Workout Gym: y=60x+190

Because both gyms are equal to y, we can set them together and solve for x.

70x+50=60x+190

10x=140

x=14

You can find the cost by plugging in 14 into both of the equations. You get a cost of $1030 after 14 months

Therefore, after 14 months you will have paid the same amount for both gyms.

7 0
3 years ago
Farmer Jones, and his wife, Dr. Jones, decide to build a fence in their field, to keep the sheep safe. Since Dr. Jones is a math
NISA [10]

Answer:A=\frac{14}{9}\cdot \sqrt{2}\ unit^2

Step-by-step explanation:

Given

Two curves are given

y=10 x^2

and y=x^2+2

the two curves intersect at

10x^2=x^2+2

x=\pm \frac{\sqrt{2}}{3}

to get the we need to integrate the curves over x axis

A=\int_{-\frac{\sqrt{2}}{3}}^{\frac{\sqrt{2}}{3}}\left ( x^2+3-10x^2\right )dx

A=2\int_{0}^{\frac{\sqrt{2}}{3}}\left ( 3-9x^2\right )dx

A=2\left [ 3\left ( \frac{\sqrt{2}}{3}\right )-\frac{9}{3}\left ( \frac{\sqrt{2}}{3}\right )^3\right ]

A=2\sqrt{2}\left [ 1-\frac{2}{9}\right ]

A=\frac{14}{9}\cdot \sqrt{2}\ unit^2

3 0
3 years ago
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