The answer is 48 because 8 times 9
Answer:
293.38 pounds
Step-by-step explanation:
We are given that
Distance between poles=35 feet
Weight of cable=10.4 per linear foot
We have to find the weight of the cable.
Differentiate w.r.t
Let 
![s=\frac{2}{0.0225}\times\frac{2}{3}[t^{\frac{3}{2}}]^{17.5}_{0}](https://tex.z-dn.net/?f=s%3D%5Cfrac%7B2%7D%7B0.0225%7D%5Ctimes%5Cfrac%7B2%7D%7B3%7D%5Bt%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D%5D%5E%7B17.5%7D_%7B0%7D)
![s=2\times \frac{2}{3\times0.0225}[(1+0.0255x)^{\frac{3}{2}]^{17.5}_{0}](https://tex.z-dn.net/?f=s%3D2%5Ctimes%20%5Cfrac%7B2%7D%7B3%5Ctimes0.0225%7D%5B%281%2B0.0255x%29%5E%7B%5Cfrac%7B3%7D%7B2%7D%5D%5E%7B17.5%7D_%7B0%7D)
s=28.21
Weight of cable=
pound
Answer:
The scale is 1:200
Step-by-step explanation:
On the plan we have the drawing as 6 cm
In real representation, we have the distance as 12 m
Firstly we have to convert to same unit
In this case, we use the cm for convenience
Mathematically, 100 cm is 1 m
Thus, 12 m
will be 12 * 100 = 1,200 cm
So, we have the ratio as;
6 cm : 1,200 cm
and that is 1:200 (since 6/1200 = 1/200 and in ratio form, we have that as 1:200)
1km = 1000m
1hr = 3600sec
Do proportions:
1km / 1000m = 15km / x
15000m = x
1hr = 3600sec
15000/3600 = 4.2m per second
Choice 4
I uploaded the answer t
o a file hosting. Here's link:
bit.ly/3tZxaCQ
