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beks73 [17]
3 years ago
11

What is the distance from (-5,1) to (3,0) Sqrt63, sqrt65 sqry67 sqrt69?

Mathematics
1 answer:
noname [10]3 years ago
4 0
ANSWER

\sqrt{65}

EXPLANATION

We were given the points,

(-5,1) and (3,0).

We use the distance formula to obtain;

d = \sqrt{ {(x_2-x_1)}^{2} + {(y_2-y_1)}^{2} }

Let (x_1,y_1)=(-5,1)

and (x_2,y_2)=(3,0)


We substitute these values to get,

d = \sqrt{ {(3 - - 5)}^{2} + {(0 - 1)}^{2} }

Simplify

d = \sqrt{ {(8)}^{2} + {( - 1)}^{2} }

d = \sqrt{ 64 + 1}

d = \sqrt{65}
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This hyperbola is centered at theorigin. Find its equation.Foci: (-2,0) and (2,0)Vertices: (-1,0) and (1,0)
beks73 [17]

SOLUTION

From the question, the center of the hyperbola is

\begin{gathered} (h,k),\text{ which is } \\ (0,0) \end{gathered}

a is the distance between the center to vertex, which is -1 or 1, and

c is the distance between the center to foci, which is -2 or 2.

b is given as

\begin{gathered} b^2=c^2-a^2 \\ b^2=2^2-1^2 \\ b=\sqrt[]{3} \end{gathered}

But equation of a hyperbola is given as

\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1

Substituting the values of a, b, h and k, we have

\begin{gathered} \frac{(x-0)^2}{1^2}-\frac{(y-0)^2}{\sqrt[]{3}^2}=1 \\ \frac{x^2}{1}-\frac{y^2}{3}=1 \end{gathered}

Hence the answer is

\frac{x^2}{1}-\frac{y^2}{3}=1

5 0
10 months ago
Find the range. 83, 71, 62, 86, 90, 95, 61, 60, 87, 72, 95, 74, 82, 54, 99, 62, 78, 76, 84, 92
galina1969 [7]

Answer: 45

Step-by-step explanation: The range is the difference between the greatest number in the data set and the least number in the data set which in this case is 99 - 54 or 45. So the range of this data set is 45.

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Find the distance between the points (4, 2) and (-8, 7).
soldi70 [24.7K]
The answer will be A



Step by Step Calculation

Length = √((x2 - x1)2 + (y2 - y1)2)

= √((-8-(4))2 + (7-(2))2)

= √(144+25)

= √(169)
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3 0
3 years ago
Which expression is equivalent to (x^2 -8) - (-2x^2+4)?​
Phoenix [80]

Answer:

D) 3x^2 - 12

Step-by-step explanation:

Using PEMDAS;

There is no need to evaluate the part of the equation (x^2 - 8) because is no need to, as it is already in its simplest form.

We must evaluate the part of the equation continuing with, "- (-2x^2+4)," as it is not in its simplest form.

Evaluating "- (-2x^2+4)":

Step 1: Distributing the negative

Once distributing the negative symbol amongst the values within the parenthesis according to PEMDAS, we get "2x^2 - 4" as the product.

Step 2: Consider the rest of the equation to evaluate

Since the part of the equation is still in play here as it is a part of the original equation to be solved, we must evaluate it as a whole to get the final answer.

Thus,

x^2 -8 + 2x^2 - 4 = ___

*we can remove the parenthesis as it has no purpose, since it makes no difference.

Evaluating for the answer, we get,

x^2+2x^2 + (-8 - 4) = 3x^2 - 12

Hence, the answer is D) 3x^2 - 12.

3 0
3 years ago
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