2/5× = ?<br><br><br>I don't understand how to answer this

AB has a vértices at (-5,1) and (-3,7). After a transformation, the image had endpoints at (3,-1) and (5,5). Describe the transf

Scrat [10]

That looks like a translation; let's check. We have

A(-5,1), B(-3,7), A'(3,-1), B'(5,5)

If it's a translation by T(x,y) we'd have

A' = A + T

B' = B + T

so

T = A' - A = (3,-1) - (-5,1) = (8,-2)

and also

T = B' - B = (5, 5) - (-3, 7) = (8,-2)

They're the same so we've verified this transformation is a translation by (8,-2), eight right, two down.

5 0

2 years ago

Read 2 more answers

A circle is centered at the origin and contains the point (-6, -8). What is the area of this circle?

gogolik [260]

Answer:

314 units²

Step-by-step explanation:

Centre of the circle = (0, 0)

Another point on the circle = (-6, -8)

$\text {Radius = }\sqrt{(0 - (-6))^2 + (0- (-8))^2}$

$\text {Radius = }\sqrt{6^2 + 8^2}$

$\text {Radius = }\sqrt{100}$

$\text {Radius = }10$

Area = π (10)² = 100π = 314 units²

6 0

3 years ago

Sasha is collecting cans to recycle.When she collected 180 cans she knew she haad reached 60% of her goal How many more cabs doe

Arturiano [62]

It would be 60 because 180 minus 60 is 60

8 0

3 years ago

solve the following system of equations. Enter the x-coordinate of the solution. Round answer to the nearest tenth. 5x+2y=22 -2x

melisa1 [442]

Answer:

A) 5x + 2y = 22

B) -2x + 6y = 3 We'll multiply A) by -3

A) -15x -6y = -66 Then we'll add B)

B) -2x + 6y = 3

-17x = -63

x = 3.7058823529

y = 1.7352941178

Step-by-step explanation:

3 0

2 years ago

Find the longer leg of the triangle.

Paha777 [63]

Answer:

Choice A. 3.

Step-by-step explanation:

The triangle in question is a right triangle.

The length of the hypotenuse (the side opposite to the right angle) is given.
The measure of one of the acute angle is also given.

As a result, the length of both legs can be found directly using the sine function and the cosine function.

Let $\text{Opposite}$ denotes the length of the side opposite to the $30^{\circ}$ acute angle, and $\text{Adjacent}$ be the length of the side next to this $30^{\circ}$ acute angle.

$\displaystyle \begin{aligned}\text{Opposite} &= \text{Hypotenuse} \times \sin{30^{\circ}}\\ &=2\sqrt{3}\times \frac{1}{2} \\&= \sqrt{3}\end{aligned}$ .

Similarly,

$\displaystyle \begin{aligned}\text{Adjacent} &= \text{Hypotenuse} \times \cos{30^{\circ}}\\ &=2\sqrt{3}\times \frac{\sqrt{3}}{2} \\&= 3\end{aligned}$ .

The longer leg in this case is the one adjacent to the $30^{\circ}$ acute angle. The answer will be $3$ .

There's a shortcut to the answer. Notice that $\sin{30^{\circ}} < \cos{30^{\circ}}$ . The cosine of an acute angle is directly related to the adjacent leg. In other words, the leg adjacent to the $30^{\circ}$ angle will be the longer leg. There will be no need to find the length of the opposite leg.