An athletic field is a 56 yd-by-112 yd rectangle, with a semicircle at each of the short sides. A running track 10 yd wide sur
rounds the field. If the track is divided into eight lanes of equal width, with lane 1 being the inner-most and lane 8 being the outer-most lane, what is the distance around the track along the inside edge of each lane?
The question is about perimeters at inner dimensions of the lanes. Perimeter = 2*longer dimension+ pi*shorter dimensions Distance between lanes = 10/8 = 1.25 yards (Note: every movement outwards increases the shorter distance by twice this spacing dimension).
Therefore, along the inside edge of each lane, the perimeters are as computed below:
Lane 1: 2*112 + pi*56 = 399.93 yards Lane 2: 2*112 + pi*(56+2*1.25) = 407.78 yards Lane 3: 2*112 + pi*(56+4*1.25) = 415.64 yards Lane 4: 2*112 + pi*(56+6*1.25) = 423.49 yards Lane 5: 2*112 + pi*(56+8*1.25) = 431. 35 yards Lane 6: 2*112 + pi*(56+10*1.25) = 439.20 yards Lane 7: 2*112 + pi*(56+12*1.25) = 447.05 yards Lane 8: 2*112 + pi*(56+14*1.25) = 454.91 yards
Step-by-step explanation: 1/4 of 1 is 1/4. 1/4 of 3/4 is .1875 which also equals 3/16. Add 1/4 and 3/16 to get 7/16 cups of sugar or 0.4375. Hope this helps!
