Indefinite integral need help pleaseeeeeee

1 answer:

7 0

necessary to make a whole complete; essential or fundamental or or denoted by an integer.

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solong [7]

Answer:im in 9th so im going to say 3)30/y\80

Step-by-step explanation:

5 0

3 years ago

irinina [24]

Answer:

x^2(3x-2) cubic inches OR in^3

3x { 3 [ 3x ( x - 2 ) + 4 ] } - 8 cubic inches OR in^3

I AM UNAWARE IF YOU ASKED THAT ONE SIDE IS (3X-2) OR ALL. I WILL ANSWER BOTH PARTS

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NOTE: '^' MEANS TO THE POWER OF..

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Volume = v, abc = 3 sides of cube (height, width, length)

Using the formula for volume in a cube,

$v = abc$

We can solve this.

If one side is (3x-2)in,

x^2(3x-2) cubic inches OR in^3

If all sides are (3x-2)in,

Use the formula,

$(a - b) ^{3} = {a}^{3} + 3ab(b - a) - {b}^{3}$

We can solve this.

(3x-2)(3x-2)(3x-2) = v
(3x-2)^3 = v.... 3x = a and -2 = b
(3x)^3 + [(3)(3x)(2)][2-3x] - (2)^3 = v
27x^3 + 18x(2-3x) -8 = v
(27x^3 + 36x - 54x^2) - 8 = v.. Terms inside brackets - take 3x as common and leave out 8
3x(9x^2 -18x +12) = v... Take 3 as common again in the brackets
3x [ 3 ([3x^2 -6x] + 4) -8 = v....Take 3x common in the terms in square brackets
3x [ 3 [ 3x (x-2) + 4 ]] - 8 = v
3x { 3 [ 3x ( x - 2 ) + 4 ] } - 8 = v

3x { 3 [ 3x ( x - 2 ) + 4 ] } - 8 cubic inches OR in^3

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5 0

1 year ago

Gennadij [26K]

Answer:

$\frac{(x+2)^2}{121} + \frac{(y-1)^2}{169} = 1$