Construct a parallelogram ABCD such that AB=9 Cm, BC=6cm and ABC=115 degress.

Mathematics

2 answers:

lara31 [8.8K]4 years ago

6 0

Answer:

1.BD=AC

AC^2=(9^2)+(6^2)-2(9)(6)COS115

AC^2=117-108COS115

AC=√71.358

AC=8.447//1.BD=AC

AC^2=(9^2)+(6^2)-2(9)(6)COS115

AC^2=117-108COS115

AC=√71.358

AC=8.447//

Step-by-step explanation:

kkurt [141]4 years ago

3 0

1.BD=AC
AC^2=(9^2)+(6^2)-2(9)(6)COS115
AC^2=117-108COS115
AC=√71.358
AC=8.447//

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