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Vanyuwa [196]
4 years ago
6

The length of a rectangle is 3 cm longer than its width. if the perimeter of the rectangle is 46 cm , find its area.

Mathematics
1 answer:
shusha [124]4 years ago
7 0
A) L = W + 3
B) 2L + 2W = 46
Putting equation A into B
2 * (W+3) + 2W = 46
2W + 6 + 2W = 46
4W = 40
Width = 10
Length = 13

Area = Length * Width
Area = 13 * 10
Area = 130 square centimeters




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Answer:

30, 20

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Multiply a big number with 3. Such as 30, or 20.

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A sea turtle swims at a speed of 27 kilometers per hour. A girl swims 14 decimeters per second. 1 m = 10 dm 1000 m = 1 km How mu
insens350 [35]
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v_{g} = (14 \, \frac{dm}{s} )*( \frac{1}{10} \, \frac{m}{dm} )*(60 \, \frac{s}{min} ) = 84 \, \frac{m}{min}

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4 0
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5 0
2 years ago
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For this problem, we are going to have to use our order of operations, which is: Parentheses, Exponents, Multiplication and Division, and Addition and Subtraction (often abbreviated PEMDAS).


First, let's see if there are any parentheses. There is one set of parentheses which we will have to remove. To do this, we will simply multiply the -4 by the 6, given us a value of -24 to take the place of the -4(6). Now our problem is:

\dfrac{12^2 - 24 + 1}{11^2}


Next, we will check for exponents. There are exponents, so we will need to take care of those. 12^2 is equal to 144, and 11^2 is equal to 121. We can now substitute these values into the original expression to get:

\dfrac{144 - 24 + 1}{121}


Now, we will check for any multiplication or division. Besides the entire expression (which is a fraction), there is none, so we will move on to the next step: Addition and Subtraction. You can see there is addition and subtraction in the numerator. 144 - 24 is equal to 120, and 120 + 1 is equal to 121. Our problem is now:

\dfrac{121}{121} = \boxed{1}


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8 0
4 years ago
The longer base of an isosceles trapezoid joins points (-3, -2) and (7, -2). One endpoint of the shorter base is (-1, 4). What a
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(5,4)

Step-by-step explanation:

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From the graph in the attachment the coordinates of the other endpoints is (5,4).

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