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2 years ago

Plz help :)))))))))))))))))))))))))

Mathematics

1 answer:

solong [7]2 years ago

5 0

Answer:im in 9th so im going to say 3)30/y\80

Step-by-step explanation:

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Over the last three evenings, Ashley received a total of 106 phone calls at the call center. The third evening, she received 2 t

V125BC [204]

Change X and Z. X is first evening
Y is second
Z is third evening

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3 years ago

TIMED

Rudik [331]

-x^2 + 4x + 12 = -3x + 24

-> x^2 - 7x + 12 = 0

-> (x-3)(x-4) = 0

-> x= 3 or 4

so y = 15 when x = 3, y = 12 when x = 4

6 0

3 years ago

Read 2 more answers

I need help on my story problems

victus00 [196]

1) 3/4 - 1/2 = 3/4 - 2/4 = 1/4. Vanessa's brothers ate half of the cake.

2) 1.75 + 2.4 = 4.15. 6.5 - 4.15 = 2.35. 4.15 = 2.35 = 1.8. Chad hiked 1.8 ore miles in the morning than in the afternoon.

8 0

3 years ago

Determine whether the improper integral converges or diverges, and find the value of each that converges.

Brrunno [24]

Answer:

Converges at -1

Step-by-step explanation:

The integral converges if the limit exists, if the limit does not exist or if the limit is infinity it diverges.

We will make use of integral by parts to determine:

let:

$u=x$ $dv=e^(2x)\cdot{dx}$

$du=dx$ $v=2\cdot{e^(2x)}$

$\int\limits^a_b {u} \, dv = uv -\int\limits^a_b {v} \, du$

$\int\limits^a_b {x\cdot{e^2^x} \, dx =2xe^2^x- \int\limits^a_b {2e^2^x} \, dx$

$\int\limits^a_b {xe^2^x} \, dx = 2xe^2^x-2e^2^x-C$

We can therefore determine that if x tends to 0 the limit is -1

$\lim_{x \to \0} 2xe^2^x-2e^2^x=0-1=-1$

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3 years ago

Help with this please i have a few minutes left!!!!

lara [203]

Answer: 5.44449

step-by-step explanation:

5 0

3 years ago