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victus00 [196]
3 years ago
6

-5-(15Y-1)=2(7Y-16)=Y         What does Y equal?                     Show work

Mathematics
1 answer:
iren [92.7K]3 years ago
8 0

-5-(15Y-1) = 2(7Y-16)

-5-15Y+1 = 14Y-32

32-4 = 19Y

Y = 28/19

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All the 5th graders at Lincoln Elementary School will go on a field trip to the science museum. Counting all the children, teach
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The answer must be a whole number because for example how are you suppose to fit half a child on a bus that can hold 44 people when it already holds that amount.

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3 0
2 years ago
The marketing club at school is opening a student store. They randomly survey 50 students about how much money they spend on lun
Luden [163]

Answer:

The expected value for a student to spend on lunch each day = $5.18

Step-by-step explanation:

Given the data:

Number of students______$ spent

2 students______________$10

1 student________________$8

12 students______________$6

23 students______________$5

8 students_______________$4

4 students_______________$3

Sample size, n = 50.

Let's first find the value on each amount spent with the formula:

\frac{num. of students}{sample size} * dollar spent

Therefore,

For $10:

\frac{2}{50} * 10 = 0.4

For $8:

\frac{1}{50} * 8 = 0.16 l

For $6:

\frac{12}{50} * 6 = 1.44

For $5:

\frac{23}{50} * 5 = 2.3

For $4:

\frac{8}{50} * 4 = 0.64

For $3:

\frac{4}{50} * 3 = 0.24

To find the expected value a student spends on lunch each day, let's add all the values together.

Expected value =

$0.4 + $0.16 + 1.44 +$2.3 + $0.64 + $0.24

= $5.18

Therefore, the expected value for a student to spend on lunch each day is $5.18

7 0
2 years ago
Definition: The statement formed when an equal sign is placed between two expressions is called an
melamori03 [73]

Answer:

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7 0
3 years ago
Blood type AB is the rarest blood type, occurring in only 4% of the population in the United States. In Australia, only 1.5% of
Umnica [9.8K]

Answer:

a. X is a binomial random variable with n = 50 and p = 0.04

b. Y is a binomial random variable with n = 40 and p = 0.015

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

X: the number of US residents (out of 50) with blood type AB.

Blood type AB is the rarest blood type, occurring in only 4% of the population in the United States

This means that p = 0.04, n = 50

Y: the number of Australians (out of 40) with blood type AB.

In Australia, only 1.5% of the population has blood type AB.

This means that p = 0.015, n = 40

Z: the total number of individuals (out of 90) with blood type AB.

Here

n = 90, p = 0.04*\frac{50}{90} + 0.015*\frac{40}{90} = 0.0289

Which of the following is true about the random variables X, Y, and Z?

Options a and b are true, while c is false.

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