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victus00 [196]
4 years ago
6

-5-(15Y-1)=2(7Y-16)=Y         What does Y equal?                     Show work

Mathematics
1 answer:
iren [92.7K]4 years ago
8 0

-5-(15Y-1) = 2(7Y-16)

-5-15Y+1 = 14Y-32

32-4 = 19Y

Y = 28/19

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Plz help me with this! Thx in advance! <br> (I need to show work)
andrew-mc [135]
A. 35/100 * 240 = 35 * 240 / 100 = 84
B.125/100 * 80 = 125 * 80 /100 = 100
C. 60/ 75% = 60 * 100 / 75 = 8
D. 45 / 15% = 45 * 100/ 15 = 300
7 0
3 years ago
The volume of a cylinder is 4πx3 cubic units and its height is x units. Which expression represents the radius of the cylinder,
igor_vitrenko [27]

Answer:

2x

The answer is A.

4 0
3 years ago
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Convert 300 g into kilograms
babymother [125]
300 grams = 0.3 kilograms
6 0
3 years ago
A container in the shape of this cuboid holds 2 litres of water.
zysi [14]

Given:

Volume of cuboid container = 2 litres

The container has a square base.

Its height is double the length of each edge on its base.

To find:

The height of the container.

Solution:

We know that,

1 litre = 1000 cubic cm

2 litre = 2000 cubic cm

Let x be the length of each edge on its base. Then the height of the container is:

h=2x

The volume of a cuboid is:

V=l\times w\times h

Where, l is length, w is width and h is height.

Putting V=2000,\ l=x,\ w=x,\ h=2x, we get

2000=x\times x\times 2x

2000=2x^3

Divide both sides by 2.

1000=x^3

Taking cube root on both sides.

\sqrt[3]{1000}=x

10=x

Now, the height of the container is:

h=2x

h=2(10)

h=20

Therefore, the height of the container is 20 cm.

8 0
3 years ago
Consider a single spin on the spinner shown below. A circle is split into sections 1, 2, 4, and 3. A spinner is pointing at numb
vladimir2022 [97]

Answer:

The answer is "Options A, B, and E represent mutually exclusive events".

Step-by-step explanation:

Two occurrences that can happen immediately called mutually incompatible. Let's now glance at our options and figure out where the statements are mutually incompatible events.

In Option A: You could see that landing on an unwanted portion and arriving on 2 are events that are locally incompatible, even as undesirable portion contains 3 and 4, and 2 were shaded.

In Option B: Arriving on a shaded part and falling on 3 are also mutually incompatible because there are 3 on a windows azure.

In Option C: A darkened portion and an increasing amount can land while 2 would be an even number as well as on the shaded portion. That number is very much the same.

In Option D: At the same time as 4 is greater than 3 and it is situated upon an undistressed section, landing and attracting a number larger than 3 can happen.

In Option E: Landing on a shaded part and landing on even a shaded part is an excluding event, since shaders may either be shaded or unlit.

3 0
3 years ago
Read 2 more answers
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