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3 years ago

What is the y intercept of the line whose equation is y = 1/2x - 3

Mathematics

2 answers:

den301095 [7]3 years ago

7 0

The y intercept is when x=0 so y=1/2(0) -3 so y=0-3 so y=-3

aleksandrvk [35]3 years ago

4 0

Hi there!
The y-intercept of the equation y = 1/2x - 3 is (0,-3).

This is because in the equation y=mx+b, the b represents the y-intercept. Since the equation of the line you were given is in y=mx+b form, you're able to easily find the y-intercept. When asked for the y-intercept, it is always best to give it as a point, you can use this - (0,y) - the y representing the y-intercept.

If there's anything else that I can help you with, please let me know! :)

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Which of the following is true about the graph of f(x)=7^x. Select all that apply.

marishachu [46]

Answer:

Step-by-step explanation:

If it intersects the x axis, then y = 0. This is not possible, as you can plug in x to be 1/100000000000000000000000000000000000, or something very tiny, but it will never get 0. So, A is not a choice.

This also means B is not a choice.

If C is a choice, then it does not intercept the y axis, or x cannot be 0. This is not true, because (0, 1) is on the graph.

Finally, we have D. It intercepts the y axis (we have proven this in C). So, this is the only answer choice that is correct.

7 0

2 years ago

Use Gauss-Jordan elimination to solve the following linear system.

marysya [2.9K]

Just put the coefients in to a matrix

1x-6y-3z=4
-2x+0y-3z=-8
-2x+2y-3z=-14

$\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\-2&2&-3|-14\end{array}\right]$
mulstiply 2nd row by -1 and add to 3rd
$\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\0&2&0|-6\end{array}\right]$
divde last row by 2
$\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\0&1&0|-3\end{array}\right]$
multiply 2rd row by 6 and add to top one
$\left[\begin{array}{ccc}1&0&-3|-14\\-2&0&-3|-8\\0&1&0|-3\end{array}\right]$
multiply 1st row by -1 and add to 2nd
$\left[\begin{array}{ccc}1&0&-3|-14\\-3&0&0|6\\0&1&0|-3\end{array}\right]$
divide 2nd row by -3
$\left[\begin{array}{ccc}1&0&-3|-14\\1&0&0|-2\\0&1&0|-3\end{array}\right]$
mulstiply 2nd row by -1 and add to 1st row
$\left[\begin{array}{ccc}0&0&-3|-12\\1&0&0|-2\\0&1&0|-3\end{array}\right]$
divide 1st row by -3
$\left[\begin{array}{ccc}0&0&1|4\\1&0&0|-2\\0&1&0|-3\end{array}\right]$

rerange
$\left[\begin{array}{ccc}1&0&0|-2\\0&1&0|-3\\0&0&1| 4\end{array}\right]$

x=-2
y=-3
z=4
(x,y,z)
(-2,-3,4)

B is answer

7 0

2 years ago

Drag each label to the correct location on the table . Triangle EFG . Rectangle PQRS . Triangle TUV . Rectangle ABCD . Your choi

Tanya [424]

Answer:

there should be a pic or a diagram

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

A shop sells newspapers for a profit of 0.5%. His sales for the month of January were $8341.50. How much of this is profit?

Doss [256]

Amount of sales of newspapers for the month of January = $8341.50
Percentage of profit for which the newspaper is sold = 0.5%
Then
Amount of profit made in the month of January = 0.5% * 8341.50 dollars
   = (0.5/100) * 8341.50 dollars
   = 4170.75/100 dollars
   = 41.707 dollars
   = 41.71 dollars
So the shop makes a profit of $41.71 in the month of January by selling newspapers worth $8341.50. I hope the procedure is perfectly clear for you to understand.

8 0

3 years ago

natta225 [31]

V=1/3(pi)(r)^2(h)
V=1/3(pi)(9)^2(15)
V=1/3(3.14)(81)(15)
Then multiply all numbers in parentheses:
3815.1/3=1271.7 cm^3

Hope this Helps!

3 0

3 years ago