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Alexeev081 [22]

2 years ago

13

Nancy joined Movies Extraordinaire for a $8 fee and an agreement to pay $1.99 per movie she rents. The equation for her total co

st is y = 1.99x + 8. Predict her total cost if she rents 25 movies.
$57.75

$58.25

$60.85

$65.95

1 answer:

Anna11 [10]2 years ago

6 0

The answer is $57.75.

Step by Step:

Take the amount of movies ( x ) multiplied by the cost of each ( $1.99 ) and add the fee. ( $8 )

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lana66690 [7]

Answer:

(7) n = ⁴/₃

(8) x = -5

(9) d = ³/₂

(10) v = -20

Step-by-step explanation:

(7) $n-\frac{8}{9} = \frac{4}{9}$

$n-\frac{8}{9} = \frac{4}{9} \\\\Collect \ similar \ terms \ together\\\\n = \frac{4}{9} + \frac{8}{9} \\\\n = \frac{4+8}{9} \\\\n = \frac{12}{9} \\\\n = \frac{4}{3}$

(8)

$\frac{3}{2} + \ x = -\frac{7}{2}\\\\collect \ similar \ terms \ together\\\\x = -\frac{7}{2} -\frac{3}{2} \\\\x = \frac{-7-3}{2} \\\\x = \frac{-10}{2} \\\\x = -5$

(9)

$\frac{6}{5} = \frac{d}{(\frac{5}{4} )} \\\\cross \ and \ multiply\\\\5d = 6(\frac{5}{4} )\\\\5d = \frac{30}{4} \\\\d = \frac{30}{4\times 5} \\\\d = \frac{30}{20} \\\\d = \frac{3}{2} \\\\d = 1\frac{1}{2}$

(10)

$-\frac{1}{8} v = \frac{5}{2} \\\\\frac{-v}{8} = \frac{5}{2} \\\\cross \ and \ multiply\\\\-2v = 40\\\\-v = \frac{40}{2} \\\\-v = 20\\\\v = -20$

6 0

2 years ago

<img src="https://tex.z-dn.net/?f=5x-%20%5Cdfrac%7B%20%5Csqrt%7B%209%20%7B%20x%20%7D%5E%7B%202%20%7D%20-6x%2B1%20%5Cphantom%7B%5

Morgarella [4.7K]

Answer:

$=5x+1$ or $=5x-1$

Step-by-step explanation:

One is given the following equation:

$5x-\frac{\sqrt{9x^2-6x+1}}{1-3x}$

The problem asks one to simplify the expression, the first step in solving this equation is to factor the equation. Rewrite the numerator and denominator of the fraction as the product of two expressions. Remember the factoring patterns:

$(a-b)^2=a^2-2ab+b^2$

$=5x-\frac{\sqrt{9x^2-6x+1}}{1-3x}$

$=5x-\frac{\sqrt{(3x-1)^2}}{-(3x-1)}$

Now simplify the numerator. Remember, taking the square root of a squared value is the same as taking the absolute value of the expression,

$=5x-\frac{\sqrt{(3x-1)^2}}{1-3x}$

$=5x-\frac{|3x-1|}{-(3x-1)}$

Rewrite the expression without the absolute value sign in the numerator. Remember the general rule for removing the absolute value sign:

$|a-b|\\=a -b$ or $(-a-b) = b-a$

$=5x-\frac{|3x-1|}{-(3x-1)}$

$=5x-\frac{3x-1}{-(3x-1)}$ or $=5x-\frac{-(3x-1)}{-(3x-1)}$

Simplify both expressions, reduce by canceling out common terms in both the numerator and the denominator,

$=5x-\frac{3x-1}{-(3x-1)}$ or $=5x-\frac{-(3x-1)}{-(3x-1)}$

$=5x-(-1)$ or $=5x-(1)$

Simplify further by rewriting the expression without the parenthesis, remember to distribute the sign outside the parenthesis by the terms inside of the parenthesis; note that negative times negative equals positive.

$=5x-(-1)$ or $=5x-(1)$

$=5x+1$ or $=5x-1$

6 0

2 years ago

(b) dy/dx = (x - y+ 1)^2

Elanso [62]

Substitute $v(x)=x-y(x)+1$ , so that

$\dfrac{\mathrm dv}{\mathrm dx}=1-\dfrac{\mathrm dy}{\mathrm dx}$

Then the resulting ODE in $v(x)$ is separable, with

$1-\dfrac{\mathrm dv}{\mathrm dx}=v^2\implies\dfrac{\mathrm dv}{1-v^2}=\mathrm dx$

On the left, we can split into partial fractions:

$\dfrac12\left(\dfrac1{1-v}+\dfrac1{1+v}\right)\mathrm dv=\mathrm dx$

Integrating both sides gives

$\dfrac{\ln|1-v|+\ln|1+v|}2=x+C$

$\dfrac12\ln|1-v^2|=x+C$

$1-v^2=e^{2x+C}$

$v=\pm\sqrt{1-Ce^{2x}}$

Now solve for $y(x)$ :

$x-y+1=\pm\sqrt{1-Ce^{2x}}$

$\boxed{y=x+1\pm\sqrt{1-Ce^{2x}}}$

3 0

3 years ago

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krek1111 [17]

Answer:

14.3%

Step-by-step explanation:

1/7=0.142857142857

round that to the nearest tenth and that is 0.143

make it a percentage and it is 14.3%

8 0

2 years ago

Solve pls brainliest

oee [108]

Answer:

mixed no. 51/10

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3 0

2 years ago