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4 years ago

0 ml from a 2.0 m solution of hcl is diluted to 10.0 ml using deionized water. what is the concentration of the new solution?

1 answer:

3 0

The concentration would remain at 2.0m. The problem states that 0 ml from the 2.0 m solution is diluted, therefore implying that none of it was diluted. Therefore, the level of concentration of the new solution would be the same as before.

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The big bang is through to have started by an?

aalyn [17]

It was thought to have been started by an asteroid that hit earth and wiped out the dinosaurs.

6 0

3 years ago

Find the linear function Cequalsf(F) that gives the reading on the Celsius temperature scale corresponding to a reading on the

padilas [110]

Answer:

C = (5/9) F - (160/9)

They both read equal at Z = - 40

Explanation:

We are looking for a linear function so we can write the following condition

Y = aX + b

Applying it to the exercise we got C = a F + b

Let's use the facts that C = 0 when F = 32 and C = 100 when F = 212

0 = 32 a + b (1)

100 = 212 a + b (2)

From (1) b = - 32 a , when we replace this in (2) we obtain a = (5/9)

and b = - (5/9)32 = - 160/9

Finally the linear function is C = (5/9) F - (160/9)

Both readings are equal at a Z number so

Z = (5/9) Z - 160/9

(4/9) Z = -160/9 and Z = - 40

6 0

4 years ago

A huge rock at the part gets really hot during the day because of what

ladessa [460]

The sun? if not, then i have no idea. ahahaha

8 0

3 years ago

A chemist prepares a solution of iron(III) bromide (FeBr3) by measuring out 41.1 mg of FeBr3 into a 50. mL volumetric flask and

allsm [11]

Answer: The molarity of $Br^-$ anions in the chemist's solution is 0.0084 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n\times 1000}{V_s}$

where,

n = moles of solute

$V_s$ = volume of solution in ml

moles of $FeBr_3$ = $\frac{\text {given mass}}{\text {Molar mass}}=\frac{0.0411g}{295.6g/mol}=0.00014mol$

Now put all the given values in the formula of molality, we get

$Molarity=\frac{0.00014\times 1000}{50}=0.0028$

As 1 mole of $FeBr_3$ gives = 3 moles of $Br^-$

0.0028 moles of $FeBr_3$ gives = $\frac{3}{1}\times 0.0028=0.0084 moles$ of $Br^-$

Thus the molarity of $Br^-$ anions in the chemist's solution is 0.0084 M

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3 years ago

If the reaction N2 (g) + 3 H2 (g) --> 2 NH3 (g) has the concentrations 1.1 M for nitrogen, 0.75 M for hydrogen and 0.25 M fo

Luba_88 [7]

Answer: The value of $K_c$ is 0.136 and is reactant favored.

Explanation:

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_{c}$