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2 years ago

Which type of matter is composed or two or more elements that are chemically combined in a fixed proportion?

1 answer:

6 0

Hello.

When dealing with two or more elements in a fixed proportion, your answer is going to be "B.) Compound." The explanation is pretty basic when you narrow it down - think of it like the English version of a compound sentence; there are two independent clauses that have related ideas (such as this one, for example).

Let's use an example of a compound element, such as $H_{2}O$ , or Water.
This is a compound element that is composed of the two elements "Hydrogen" and "Oxygen" - for every 2 Hydrogen atoms there is one Oxygen atom.

I hope this helps!

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Equation balancing

meriva

Answer:

For a: The balanced equation is $2S(s)+3O_2(g)\rightarrow 2SO_3(g)$

For c: The balanced equation is $2NaOH(s)+H_2SO_4(aq)\rightarrow Na_2SO_4(aq)+2H_2O(l)$

Explanation:

A balanced chemical equation is one where all the individual atoms are equal on both sides of the reaction. It follows the law of conservation of mass.

For (a):

The given unbalanced equation follows:

$S(s)+O_2(g)\rightarrow SO_3(g)$

To balance the equation, we must balance the atoms by adding 2 infront of both $S(s)$ and $SO_3$ and 3 in front of $O_2$

For the balanced chemical equation:

$2S(s)+3O_2(g)\rightarrow 2SO_3(g)$

For (b):

The given balanced equation follows:

$2Al(s)+3Cl_2(g)\rightarrow 2AlCl_3(s)$

The given equation is already balanced.

For (c):

The given unbalanced equation follows:

$2NaOH(s)+H_2SO_4(aq)\rightarrow Na_2SO_4(aq)+H_2O(l)$

To balance the equation, we must balance the atoms by adding 2 infront of $H_2O(l)$

For the balanced chemical equation:

$2NaOH(s)+H_2SO_4(aq)\rightarrow Na_2SO_4(aq)+2H_2O(l)$

For (d):

The given balanced equation follows:

$C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g)$

The given equation is already balanced.

4 0

2 years ago

A sample compound contains 5.723g Ag, 0.852g S and 1.695g O. Determine its empirical formula.

Lubov Fominskaja [6]

Answer:

$Ag_2SO_4$

Explanation:

Formula for the calculation of no. of Mol is as follows:

$mol=\frac{mass\ (g)}{molecular\ mass}$

Molecular mass of Ag = 107.87 g/mol

Amount of Ag = 5.723 g

$mol\ of\ Ag=\frac{5.723\ g}{107.87\ g/mol} =0.05305\ mol$

Molecular mass of S = 32 g/mol

Amount of S = 0.852 g

$mol\ of\ S=\frac{0.852\ g}{32\ g/mol} =0.02657\ mol$

Molecular mass of O = 16 g/mol

Amount of O = 1.695 g

$mol\ of\ O=\frac{1.695\ g}{16\ g/mol} =0.10594\ mol$

In order to get integer value, divide mol by smallest no.

Therefore, divide by 0.02657

$Ag, \frac{0.05305}{0.02657} \approx 2$

$S, \frac{0.02657}{0.02657} \approx 1$

$O, \frac{0.10594}{0.02657} \approx 4$

Therefore, empirical formula of the compound = $Ag_2SO_4$

7 0

3 years ago

Read 2 more answers

A semipermeable membrane is placed between the following solutions. Which solution will decrease in volume? Solution A: 1.31% (m

Zigmanuir [339]

Answer:

Are you in flvs, if so im prettyb sure if yo look on page 3 of lesson 1.04 it tells you the answer.

Explanation:

5 0

2 years ago

Read 2 more answers

Why are large differences in temperature between the wet bulb and dry bulb thermometers are possible only at higher temperatures

photoshop1234 [79]

Answer:

At constant vapor pressure, the relative humidity decreases as the temperature increases, therefore, at higher temperature the relative humidity is low and water readily evaporates from the wet bulb thermometer that results in the cooling of the bulb such that at a given ambient temperature the very low relative humidity results in very large differences between the temperatures of the wet bulb thermometer and that of the dry bulb thermometer and the wet bulb is observed to be the colder thermometer of the two

Explanation:

8 0

2 years ago

A solution contains 90 mL of methanol, 18 mL of propanol, and 2 mL of diethyl ether. Which is the solvent in this solution?

otez555 [7]

Answer:

Methanol

Explanation:

5 0

2 years ago