Answer:
Average atomic mass = 15.86 amu.
Explanation:
Given data:
Number of atoms of Z-16.000 amu = 205
Number of atoms of Z-14.000 amu = 15
Average atomic mass = ?
Solution:
Total number of atoms = 205 + 15 = 220
Percentage of Z-16.000 = 205/220 ×100 = 93.18%
Percentage of Z-14.000 = 15/220 ×100 = 6.82 %
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass = (93.18×16.000)+(6.82×14.000) /100
Average atomic mass = 1490.88 + 95.48 / 100
Average atomic mass = 1586.36 / 100
Average atomic mass = 15.86 amu.
Answer:
The question is incomplete.(not enough data provided).
Explanation:
1 mole ------------ 6.02 x10²³ molecules
? mole ----------- 1.505 x10²³ molecules
1.505x10²³ / 6.02x10²³ => 0.25 moles
hope this helps!
Answer:
magnesium ion Hg2+ cation is formed
<span>The correct answer is (C) 0.2 mole MgCl2.
according to Van't Hoff factor rule which is the ratio between the actual
concentration of the particles produced when the substance dissolved and
the concentration of the substance as measured from its mass, so here 0.2
mole MgCl2 is the higher van't Hoff factor as it has more ions than other
choices and the higher concentration.
and when the boiling point formula is delta Tb = Kb * m * i.
when delta Tb is the change in boiling point.
and Kb is molal boiling point constant
and m is the molality of the solution
and i is Van't Hoff factor.
so we can see the relationship between i and delta Tb, the greater Van't Hoff factor the higher the boiling point. so 0.2 MgCl2 is the higher boiling point as it is the greater van't Hoff factor.</span>