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maks197457 [2]
4 years ago
8

Suppose you have a bucket of sand containing 2.5 billion grains of sand (2.5 x 10 grains). Most of the grains of sand are white,

but there are some brown grains mixed evenly throughout. Number If the concentration of brown sand is 2.0%, how many grains of brown sand are in the bucket? brown grains Number If the concentration of brown sand is 2.0 ppm I how many grains of brown sand are in the bucket?
Chemistry
1 answer:
anzhelika [568]4 years ago
3 0

Answer:

a. 5.0 x 10⁷ brown grains = 50 million

b. 5.0 x 10³ brown grains = 5000

Explanation:

The concentration of 2 % brown sand means we have for every 100 grains of sand 2 are brown.

We need to calculate the number of brown sand in the bucket as follows:

= 2.5 x 10⁹  billion grains of sand x  (2 brown grains/ 100 grains of sand)

= 5.0 x 10⁷ brown grains

Likewise if the concentration of brown sand is 2.0 ppm, it mean that we have 2 brown grain per every million grains of sand.

= 2.5 x 10⁹ billion grains of sand x ( 2.0 brown grains/10⁶ grains of sand )

= 5.0 x 10³ brown grains

The answers make sense since a concentration of 1 part per million is ten thousandths of  a 1 percent

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Mass defect for oxygen-16 = 0. 13261 amu, in the kilograms the mass defect equals to 2.20 × 10⁻²⁸ kg.

<h3>What is mass defect?</h3>

Mass defect is the difference between the mass of of an whole atom and the combined mass of its individual particles present in that atom.

We know that, 1 amu = 1.6 × 10⁻²⁷ kg

Given that, mass defect for oxygen-16 = 0.13261 amu

To calculate this defect in terms of kilograms, we have to convert into kg unit as:

0.13261 amu = 0.13261 amu × 1.6 × 10⁻²⁷ kg/amu

0.13261 amu = 2.20 × 10⁻²⁸ kg

Hence option (2) is correct.

To know more about Mass defect, visit the below link:

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Can you separate cooking oil from a mixture of cooking oil and water by filtering
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How many grams of ammonia must you start with to make 900.00 l of a 0.140 m aqueous solution of nitric acid? assume all the reac
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You need the set of reactions that goes from ammonia to nitric acid.
<span>
1) 4NH3(g)+5O2(g)-->4NO(g)+6H2O(g)

2) 2NO(g)+O2(g)-->2NO2(g)

3) 3NO2(g)+H2O(l)-->2HNO3(aq)+NO(g)

State the ratio of moles of HNO3 to NH3:

4 moles of NH3 produce 4 mole of NO,

4 moles of NO produce 4 moles of NO2

4 moles of NO2 produce 4 * (2 / 3) moles of HNO3 = 8/3 moles of HNO3.

=> (8/3) moles HNO3 : 4 moles NH3

Calculate the number of moles of HNO3 in 900.00 l of 0.140 M solution

M = n / V => n = M * V = 0.140 M * 900.00 liter = 126 moles HNO3

Use proportions:

(</span><span>8/3) moles HNO3 / 4 moles NH3 = 126 moles HNO3 / x

=> x = 126 moles HNO3 * 4 moles NH3 / (8/3 moles HNO3) = 189 moles NH3

Convert moles to grams:

molar mass NH3 = 14 g/mol + 3 * 1g/mol = 17 g/mol

mass in grams = number of moles * molar mass = 189 moles * 17 g/mol = 3213 g

Answer: 3213 g.
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