<h3>
Answer:</h3>
15 moles
<h3>
Explanation:</h3>
The decomposition of boron carbonate is given by the equation;
B₂(CO₃)₃(s) → B₂O₃(s) + 3CO₂(g)
Moles of boron carbonate decomposed is 5.0 mol
To find the moles of CO₂ produced we are going to use the mole ratio.
Mole ratio of B₂(CO₃)₃ to CO₂ is 1 : 3
Therefore;
Moles of CO₂ = Moles of B₂(CO₃)₃ × 3
= 15 mol
Therefore, 15 moles of CO₂ will be produced
12 % salt is present in 125 g mixture of salt and sand.
Keep in mind that the total percentage is always 100 %
Therefore, if 12 % is the salt, remaining 88 % must be
sand.
a. The amount of mixture is 125 q. Here, 12 % of 125 is
12 * 125 / 100 = 15 g of salt is present in 125 g mixture.
b. The amount of sand can be calculated similarly, 88 %
of 125 g is 88 * 125 / 100 = 110 g of sand is present in
125 g mixture.
Answer:
3 pieces of lunch-meat and 2 slices of cheese
Explanation:
You have enough bread to make 3 sandwiches
You have enough lunch-meat to make 4 sandwiches
You have enough cheese to make 5 sandwiches
In all you have enough material to make 3 sandwiches
so if you subtract three from each number above you will have no bread, enough lunch-meat to make one sandwich and enough cheese to make two sandwiches
luch-meat for one sandwich is: 3 pieces
Cheese for two sandwiches is: 2 pieces
