Y = 1/2 x
for x = 0 → y = 1/2 · 0 = 0
for x = 2 → y = 1/2 · 2 = 1
x | 0 | 2 |
y=1/2x| 0 | 1 |
y = x + 3
for x = 0 → y = 0 + 3 = 3
for x = -3 → y = -3 + 3 = 0
x | 0 | 3 |
y=x+3|-3 | 0 |
Compose the quadratic condition in standard shape, ax2 + bx + c = 0. Recognize the values of a, b, c. Write the Quadratic Equation. At that point substitute within the values of a, b, c. Simplify. Check the arrangements.
Answer:
Step-by-step explanation:
They gave you an easy triangle. You can tell by the coordinates that X and Z are horizontally aligned, and Y and Z are vertically aligned, so Z is a right angle.
Area = 0.5(XZ)(YZ) = 0.5(3)(3) = 4.5 square units.
Answer:
13.7
Step-by-step explanation:
It forms a triangle.
They are trying to find the height, cause they say the east-bound car went east so that makes the bottom of the triangle, the width. They also give is the distance in between both cars so that's the hypotenuse so let's set up the equation...
15² - 6² = 189
now we square root it
√189 = 13.7
Step-by-step explanation:
g of load= 30 kg ( kilogram)
load at top of building=20 kg( kilogram)
building height=13 m(meter)
<h2>or"= total work done=?</h2>
<h3> or"=. power developed by him= ? </h3>
now ,
30*20*13÷20
again ,30*20*13
________
20
answer,= 390
