Ask question

Ask question

All categories

3 years ago

10

The slope of the line below is-2. Which of the following is the point-slope

1 answer:

Aleksandr [31]3 years ago

7 0

Answer:

A

Step-by-step explanation:

y-y1 = m(x-x1)

You might be interested in

mamaluj [8]

Answer:

10=16[ by cost]

Step-by-step explanation: the cost of 10 chairs is x.

the cost 16 chairs is also x. 10x = 16x

4x is loss.

Profit or Gain = Selling price – Cost price. Loss = Cost price – Selling price. Profit Percentage = [Profit/C.P.]×100. Percentage Loss = [Loss/C.P.]×100.

In simple way, we can say that sp- cp[ when it is a gain], cp -sp[ when it is a loss]. here it is a loss as well as a gain. so do both according to the formula

3 0

3 years ago

Find the value of each variable. write your answers in simplest radical form

erica [24]

Answer:

y=3.364

x=4

Step-by-step explanation:

hope this helps

7 0

2 years ago

Which expression is equivalent to 6(2x + 4)

aleksley [76]

Answer:

12x+24

Step-by-step explanation:

by multiplying the number 6 into the term inside of the bracket gives 12x + 24

6 0

2 years ago

The Resource Conservation and Recovery Act mandates the tracking and disposal of hazardous waste produced at U.S. facilities. Pr

aniked [119]

Answer:

(a) $E(X) = 0.383$

The expected number in the sample that treats hazardous waste on-site is 0.383.

(b) $P(x = 4) = 0.000169$

There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

Step-by-step explanation:

Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.

N = 209

Only eight of these facilities treated hazardous waste on-site.

r = 8

a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?

n = 10

The expected number in the sample that treats hazardous waste on-site is given by

$E(X) = \frac{n \times r}{N}$

$E(X) = \frac{10 \times 8}{209}$

$E(X) = \frac{80}{209}$

$E(X) = 0.383$

Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.

b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site

The probability is given by

$P(x = 4) = \frac{\binom{r}{x} \binom{N - r}{n - x}}{\binom{N}{n}}$

For the given case, we have

N = 209

n = 10

r = 8

x = 4

$P(x = 4) = \frac{\binom{8}{4} \binom{209 - 8}{10 - 4}}{\binom{209}{10}}$

$P(x = 4) = \frac{\binom{8}{4} \binom{201}{6}}{\binom{209}{10}}$

$$ P(x = 4) = \frac{70 \times 84944276340}{35216131179263320}$

$P(x = 4) = 0.000169$

Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

8 0

2 years ago

Plss help this is due tomorrow !! :((

VladimirAG [237]

Answer:

A y= -3/4+6

Step-by-step explanation

I hope this helps good luck

I'm 100% sure

Good luck god bless you pass have a nice day

3 0

2 years ago

Read 2 more answers