I think the answer is .602050
Answer:
-4 to 3
Step-by-step explanation:
look at the first number in each set then find the smallest and the biggest that is how you find range
Examples of rational numbers are: -2 = -2/1, -5 = -5/1, -14 = -14/1, 1/2, 2/3, 5/8, 3/4, 17/5, . 6 = 6/10 = 3/5, . 25 = 1/4, . 33 = 33/100, 2¾ = 11/4, 3⅓ = 10/3, .
Answer: You divided 24 by 3 then you take the answer
Step-by-step explanation:I hope it help
The expected length of code for one encoded symbol is
where 
is the probability of picking the letter 
, and 
is the length of code needed to encode . is given to us, and we have
so that we expect a contribution of
bits to the code per encoded letter. For a string of length 
, we would then expect ![E[L]=1.375n](https://tex.z-dn.net/?f=E%5BL%5D%3D1.375n)
.
By definition of variance, we have
![\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2](https://tex.z-dn.net/?f=%5Cmathrm%7BVar%7D%5BL%5D%3DE%5Cleft%5B%28L-E%5BL%5D%29%5E2%5Cright%5D%3DE%5BL%5E2%5D-E%5BL%5D%5E2)
For a string consisting of one letter, we have
so that the variance for the length such a string is
"squared" bits per encoded letter. For a string of length , we would get ![\mathrm{Var}[L]=1.859n](https://tex.z-dn.net/?f=%5Cmathrm%7BVar%7D%5BL%5D%3D1.859n)
.
