A. -1/4(x-10)^2
The screenshot shows the graph
Answer:
6.28
Step-by-step explanation:
2 x 3.14
The equation of the line containing (- 4,5) and perpendicular to the line 5x - 3y = 4 is y = -3 / 5 x + 13 / 5
<h3>How to find the equation of a line?</h3>
The equation of a line can be represented as follows:
y = mx + b
where
Therefore, the equation passes through (-4, 5) and perpendicular to 5x - 3y = 4
Hence,
perpendicular lines follows the rule below:
m₁m₂ = -1
Hence,
5x - 3y = 4
5x - 4 = 3y
y = 5/ 3 x - 4 / 3
m₁ = 5 / 3
5/3 m₂ = -1
m₂ = - 3 / 5
Hence,
using (-4, 5)
5 = - 3 / 5 (-4) + b
5 = 12 / 5 + b
b = 5 - 12 / 5 = 25 - 12 /5 = 13 / 5
Therefore,
y = -3 / 5 x + 13 / 5
learn more on equation of a line here: brainly.com/question/10727767
#SPJ1
Answer:
A) JK and AB =
![[tex] \boxed{( \theta) = \f{12}{( \theta)} }](https://tex.z-dn.net/?f=%5Btex%5D%20%5Cboxed%7B%28%20%5Ctheta%29%20%3D%20%5Cf%7B12%7D%7B%28%20%5Ctheta%29%7D%20%7D)
So, =》 
=》 
[/tex]
B) AABC
![[tex] \boxed{( \theta) = {1}{( \theta)} }](https://tex.z-dn.net/?f=%5Btex%5D%20%5Cboxed%7B%28%20%5Ctheta%29%20%3D%20%7B1%7D%7B%28%20%5Ctheta%29%7D%20%7D)
So, 
C) AABM:
![[tex] e \fbox{: }](https://tex.z-dn.net/?f=%5Btex%5D%20e%20%5Cfbox%7B%3A%20%7D)
The value of k for which 
is 
ans[/tex]
----------
Answer:
Step-by-step explanation:
Triangle DEF is a right angle triangle.
From the given right angle triangle,
DE represents the hypotenuse of the right angle triangle.
With ∠E as the reference angle,
EF represents the adjacent side of the right angle triangle.
DF represents the opposite side of the right angle triangle.
To determine EF, we would apply
trigonometric ratio
Cos θ = opposite side/hypotenuse. Therefore,
Cos 49 = EF/8
EF = 8Cos49 = 8 × 0.6561
EF = 5.2488
Rounding to the nearest tenth, it becomes 5.2
