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Yakvenalex [24]
3 years ago
8

What is the volume, to the nearest whole cubic inch, of a cylinder with a height of 10 inches and a radius of 8 inches? Use PI=3

.14 and round your answer to the whole number.
Mathematics
2 answers:
HACTEHA [7]3 years ago
7 0
V= pi *r ^2 *h  for a cylinder 
V= 3.14* 10* (8*8)
V=3.14*640=2009.60
if you rounded is 2010 in^3
rodikova [14]3 years ago
6 0

Answer:

2010 in³

Step-by-step explanation:

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Pietro has $75. He used 3/5 of his money to buy a new pair of running shoes. How much did Pietro spend on his new shoes
cupoosta [38]

Step-by-step explanation:

HI Sofia!

So this is how you find the answer.

Amount of money pietro has=$75

Amount of money he spent on shoes=3/5 of 75

=3/5*75= 45

Thus, Pietro spent $45 on shoes.

7 0
2 years ago
Read 2 more answers
What is the slope of the line containing the points (1,10) and (-3,10)
PIT_PIT [208]

Answer:

0

Step-by-step explanation:

Slope is Rise over Run (y / x).

For 2 points, you would take the difference of y-coordinates and divide by the difference of x-coordinates.

(Y1 - Y2) / (X1 - X2)

Since both y-coordinates are the same (ten minus ten), your slope is zero (zero divided by anything is zero).

7 0
3 years ago
Solve the following equations for x (5 points each). (a)-3x+10=34
yan [13]

Answer:

x = -8

Step-by-step explanation:

6 0
3 years ago
3. Two quantities, x and y, are in a
frez [133]

Answer:

y = x + 1.8

Step-by-step explanation:

6 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Kitty [74]

Answer:   (-2, 5) and (2, -3)

<u>Step-by-step explanation:</u>

Graph the line y = -2x + 1 (which is in y = mx + b format) by plotting the y-intercept (b = 1) on the y-axis and then using the slope (m = -2) to plot the second point by going down 2 and right 1 unit from the first point:

        y - intercept = (0, 1)            2nd point = ( -1, 1).

Graph the parabola y = x² - 2x - 3 by first plotting the vertex and then plotting the y-intercept (or some other point):

y = x^2-2x-3\quad \rightarrow \quad a=1,\ b=-2,\ c=-3\\\\\text{axis of symmetry:}\ x = \dfrac{-b}{2a}\ \longrightarrow \ x=\dfrac{-(-2)}{2(1)}=\dfrac{2}{2}=1\\\\\text{y-value of vertex:}\ f(1) = (1)^2-2(1)-3\quad \longrightarrow \quad y = 1 - 2 - 3=-4\\\\\text{y-intercept:}\ f(0)= (0)^2-2(0)-3\ \longrightarrow \ y=0 - 0 - 3 = -3 \\

         vertex = (1, -4)                2nd point (y-intercept) = (0, -3)


<em>see attached</em> - the graphs intersect at two points:  (-2, 5) and (2, -3)


8 0
3 years ago
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