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Kitty [74]
2 years ago
15

If point D is the midpoint of segment BC then what are the coordinates of point D given B(5,-2) and C (-7,-2)

Mathematics
1 answer:
Neko [114]2 years ago
5 0
Point d is at (-1, -2) find the average of the values to get the midpoint
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Through (4,-4) ; perpendicular to 6y=x-12
BARSIC [14]

y = mx + b

m = slope and b = y-intercept


We can arrange 6y = x - 12 in the form of y = mx + b

                  6y = x - 12

                    y = 1/6(x) - 2

Slope of y = 1/6(x) - 2 is 1/6. Taking the negative reciprocal of the slope we get the slope for the perpendicular line.

Negative reciprocal of 1/6 is -6.

The equation for the perpendicular line is

                  y = -6x + b

To find b we can plug in the x and y values of (4,-4) into it since it passes through those coordinates

                -4 = -6(4) + b

                 b = -4 + 6(4)

                 b = -4 + 24

                 b = 20

So the equation for the perpendicular line is y = -6x + 20

3 0
3 years ago
6. Edgar pays $67.86 for 7.8 pounds of fertilizer. What is
sineoko [7]
The answer is H. $8.70
7 0
3 years ago
Read 2 more answers
What is the perimeter of DEFG, shown?
Murrr4er [49]

Answer:

C.34

Step-by-step explanation:

you find the length which is 10 squares and the width which is 7 squares. Since the shape is a quadrilateral you add all sides to find the perimeter= 2L+2W. 2(10)+2(7)=20+14=34

4 0
3 years ago
PLEASE ANSWER
charle [14.2K]

Answer:

The slope intercept form is y=\frac{1}{2}x-5

Step-by-step explanation:

Given : Equation y+3=\frac{1}{2}(x-4)

To find : Rewrite the equation in slope-intercept form ?

Solution :

The slope-intercept form is y=mx+c

Equation y+3=\frac{1}{2}(x-4)

y+3=\frac{1}{2}x-\frac{1}{2}\times 4

y+3=\frac{1}{2}x-2

y=\frac{1}{2}x-2-3

y=\frac{1}{2}x-5

Therefore, the slope intercept form is y=\frac{1}{2}x-5

3 0
3 years ago
What is the effect of removing the outlier 11 from the following data set? (1 point)
KiRa [710]

Answer:

A The mean would increase.

Step-by-step explanation:

mean = sum of numbers ÷ how many numbers there are

the mean with the outlier 11:

(11 + 85 + 87 + 88 + 91 + 91 + 92 + 93 + 95) ÷ 9 = 81.4

the mean when removing the outlier 11:

(85 + 87 + 88 + 91 + 91 + 92 + 93 + 95) ÷ 8 = 90.25

the mean has now increased

6 0
2 years ago
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