![\bf \begin{array}{ccccccccc} &&x_1&&y_1&&x_2&&y_2\\ % (a,b) &&(~ 2 &,& 3~) % (c,d) &&(~ 4 &,& -3~) \end{array} \\\\\\ % slope = m slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-3-3}{4-2}\implies \cfrac{-6}{2}\implies \cfrac{-3}{1}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bccccccccc%7D%0A%26%26x_1%26%26y_1%26%26x_2%26%26y_2%5C%5C%0A%25%20%20%28a%2Cb%29%0A%26%26%28~%202%20%26%2C%26%203~%29%20%0A%25%20%20%28c%2Cd%29%0A%26%26%28~%204%20%26%2C%26%20-3~%29%0A%5Cend%7Barray%7D%0A%5C%5C%5C%5C%5C%5C%0A%25%20slope%20%20%3D%20m%0Aslope%20%3D%20%20m%5Cimplies%20%0A%5Ccfrac%7B%5Cstackrel%7Brise%7D%7B%20y_2-%20y_1%7D%7D%7B%5Cstackrel%7Brun%7D%7B%20x_2-%20x_1%7D%7D%5Cimplies%20%5Ccfrac%7B-3-3%7D%7B4-2%7D%5Cimplies%20%5Ccfrac%7B-6%7D%7B2%7D%5Cimplies%20%5Ccfrac%7B-3%7D%7B1%7D)
now, a line perpendicular to that one, will have a "negative reciprocal" slope, thus
Answer: 60 in
Step-by-step explanation:
Hi, to answer this question, first we have to calculate the diameter of one flotation device:
Circumference of a circle C = (3.14) (diameter)
Replacing with the values given:
62.8 =3.14 d
Solving for d (diameter)
62.8 /3.14 =d
20in = d
Now, since the three flotation devices are identical, we simply have to multiply the diameter of one device by 3 , to obtain length of the flotation devices lined up.
20x3 =60 in
Feel free to ask for more if needed or if you did not understand something.