C im pretty sure thats it
Hello.
1. Understand that this requires inverse trigonometry.
2. For A, we can use sin^-1 if we want (we could use cos^-1 or tan^-1 as well because all sides are given)
Definition of sin^-1 with how it is derived
sin(theta) = O/H <—> sin^-1(O/H)
Angle A: (When calculating an angle, ensure that your calculation is in degree mode instead of radian mode.) 2ND, then QUIT on TI
sin^-1(7/25) = 16.26020471°
(round as needed)
Angle &: (also in degree mode)
All angles of a triangle add to 180°.
1. 180° - (angle B + Angle A) = Angle &
2. 180° - (90° + 16.26020471°) = 73.73979529°
(round as needed)
To quickly check: 16° + 90° + 73° = 180°, as expected for a triangle
From the picture you provided,
The angle values make sense because that triangle represents a 30-60-90 degree triangle. (Also, a good trick is to know that the smallest angle of a triangle will always have the smallest side value, and the largest angle has the largest side value.)
Unless we have an equilateral triangle!
Good luck to you!
To add 1/2 and 5/12, make both fractions have the same denominator:
1/2 is the same as 6/12, so 6/12+5/12=11/12
Thus, B is right.
1/2 = 50%
50% is greater than 47%
2 is correct, because:
1) we have a close interval
2)we must have node on x=-5
