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o-na [289]
3 years ago
14

Given f(x) = ab-x + c. How would increasing the value of a change the graph?

Mathematics
2 answers:
alexgriva [62]3 years ago
7 0

Answer: answer is c.

Step-by-step explanation:

Yuki888 [10]3 years ago
7 0

Answer:

A) The function would increase at a faster rate

Step-by-step explanation:

Imagine that you have a graph and that in that graph A value is 1, if you increase that to 2, then your graph will automatically start to grow double what it was growing, so if you increase the value of A the change that you woul have in the graph is that the function would increase at a faster rate.

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If ∠2 and ∠3 are supplementary angles, then ∠2 and ∠3 form a linear pair true or false
Bezzdna [24]
True. Two angles of a linear pair will always be supplementary

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3 years ago
What is the slope and y-intercept for the line represented by this equation? -3x+8y= -24
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I believe its a -3...............
5 0
3 years ago
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A dog collar was originally priced at $5 but went on sale for 20% off. If Vince bought the dog collar and paid 9% sales tax, how
Vlada [557]

Answer:$4.36

Step-by-step explanation:

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3 0
3 years ago
What is the radius of a circle whose equation is x2 + y2 + 8x – 6y + 21 = 0?
s344n2d4d5 [400]

Answer:

2 units

Step-by-step explanation:

The given equation of the circle is:

x^{2} + y^{2}+8x-6y+21=0

The general equation of the circle is:

x^{2} + y^{2}+2gx+2fy+c=0

Comparing the given equation with the general equation we can say:

g = 4

f = -3

c = 21

The formula for radius of the circle is:

radius=\sqrt{g^{2} +f^{2} -c }

Using these values of the given circle, we get:

radius=\sqrt{(4)^{2}+(-3)^{2}-21}\\\\radius=\sqrt{4}\\\\radius=2

Therefore, the length of radius of the given circle is 2.

3 0
3 years ago
Find the coordinates of the circumcenter of triangle ABC with vertices A(1,4) B(1,2) and C(6,2)
Ray Of Light [21]
<span>(3.5, 3) is the circumcenter of triangle ABC. The circumcenter of a triangle is the intersection of the perpendicular bisectors of each side. All three of these perpendicular bisectors will intersect at the same point. So you have a nice self check to make sure your math is correct. Now let's calculate the equation for these bisectors. Line segment AB: Slope (4-2)/(1-1) = 2/0 = infinity. This line segment is perfectly vertical. So the bisector will be perfectly horizontal, and will pass through ((1+1)/2, (4+2)/2) = (2/2, 6/2) = (1,3). So the equation for this perpendicular bisector is y = 3. Line segment BC (2-2)/(6-1) = 0/5 = 0 This line segment is perfectly horizontal. So the bisector will be perfectly vertical, and will pass through ((1+6)/2,(2+2)/2) = (7/2, 4/2) = (3.5, 2) So the equation for this perpendicular bisector is x=3.5 So those two bisectors will intersect at point (3.5,3) which is the circumcenter of triangle ABC. Now let's do a cross check to make sure that's correct. Line segment AC Slope = (4-2)/(1-6) = 2/-5 = -2/5 The perpendicular will have slope 5/2 = 2.5. So the equation is of the form y = 2.5*x + b And will pass through the point ((1+6)/2, (4+2)/2) = (7/2, 6/2) = (3.5, 3) Plug in those coordinates and calculate b. y = 2.5x + b 3 = 2.5*3.5 + b 3 = 8.75 + b -5.75 = b So the equation for the 3rd bisector is y = 2.5x - 5.75 Now let's check if the intersection with this line against the other 2 works. Determining intersection between bisector of AC and AB y = 2.5x - 5.75 y = 3 3 = 2.5x - 5.75 8.75 = 2.5x 3.5 = x And we get the correct value. Now to check AC and BC y = 2.5x - 5.75 x = 3.5 y = 2.5*3.5 - 5.75 y = 8.75 - 5.75 y = 3 And we still get the correct intersection.</span>
6 0
3 years ago
Read 2 more answers
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