Answer:
370
Step-by-step explanation:
First find the unit rate aka price per pencil: 20 divided by 6 equals 3.333
Then find amount for all pencils
3.333 by 111 is 369.963
Then we round up to have a realistic amount of pencils to 370
1 ÷ 3 = 3 × 3 = 9
So you would have 9 1/3 chicken pot pie pieces
A. Mr. Kent interviewed the 54 students as they are going to leave the school, it is not considered to be a random sample. It is because a random sample is when a set is taken from a population. Mr. Kent interviewed the 54 who are going to leave, meaning, he didn't take a set out of that 54, he took all of them. So it is not a random sample.
b. The question that Mr. Kent asked is considered to be a leading question, so it does not seem biased.
c. If there are 54 respondents.
51 = yes, the rest is no.
= 54 - 51 = 3
= 3 is now divided to 54 = 3/54
= giving an answer of 0.0555
= 0.0555 x 100
= 5.6%
= The percent of responses that says 'no' is 5.6%
A standard deck has 52 cards.
A standard deck has 4 jacks.
A standard deck has 13 clubs.
From this, we can derive the following:
The probability of drawing a jack is 4/52 or 1/13
The probability of drawing a club is 13/52 or 1/4
But since the problem asks for drawing jack or club, therefore we should add the 2 probabilities, making 17/52. This is not the final answer yet. We know that there is a jack of clubs, therefore we need to subtract 1 from the probabilities since jack of clubs were considered in the 2 categories of probability.
With that being said, the probability of drawing a club or a jack is 16/52 or 4/13
Bonus Question:
The first thing you need to do here is find the probability of each scenario. First let's do what is given, the probability of drawing 2 aces. Since there are 4 aces in a deck of 52, we can easily say that the probability of drawing an ace is 4/52. However for our second draw, the probability of drawing a different ace is 3/51. This is so since we already drew a card that is an ace, hence we need to subtract one from the total aces (4-1) and from the total cards in the deck (52-1). In getting the probability of drawing two aces, we need to multiply the said probabilities: 4/52 and 3/51, resulting to 1/221.
For the second scenario, the drawing of 2 red cards, we just use the same concept but in this, we are already considering the 2 red cards in the first scenario, therefore the chance of drawing a red on our first draw is 24/52. For our second, we just need to subtract one card, therefore 23/51. Multiply these two and we will get 46/221.
Now, the problem asks for the chance of drawing either 2 reds or 2 aces, therefore we add the probabilities of the 2 scenarios:
46/222 + 1/221 = 47/221
Summary:
First Scenario:
4/52 + 3/51 = 1/221
Second Scenario:
24/52 + 23/51 = 46/221
Chances of drawing 2 red cards or 2 aces:
1/221 + 46/221 = 47/221
Answer:
He needs 7 more consecutive successful first serves to raise his first serve percentage to 60%.
Step-by-step explanation:
After n consecutive serves, his total number of serves is going to be n+8, since he has already served 8 times. In the best case, his number of successful first serves is n+2.
His percentage of succesful first serves is the division of the number of succesful first serves divided by the total number of serves. So
We want 
. So
He needs 7 more consecutive successful first serves to raise his first serve percentage to 60%.
