3 years ago

Anyone know this?! due soon

Mathematics

1 answer:

AVprozaik [17]3 years ago

8 0

Answer:

C is the correct answer

Step-by-step explanation:

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The frequency distribution is in the attached image.

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The midpoints of a class is calculated as the average of the bounds of the class.

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$E(X)=\dfrac{1}{N}\sum f_iX_i\\\\\\E(X)=\dfrac{1}{60}(3\cdot15+7\cdot25+18\cdot35+20\cdot45+12\cdot 55)=\dfrac{45+175+630+900+660}{60}\\\\\\E(X)=\dfrac{2,410}{60}=40.17$

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$s=\sqrt{\dfrac{1}{N-1}\sum f_i(X_i-E(X))^2}\\\\\\s=\sqrt{\dfrac{1}{59}[3(15-40.17)^2+7(25-40.17)^2+18(35-40.17)^2+20(45-40.17)^2+12(55-40.17)^2]}$

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