For a positive angle, the rotation from the initial side to the terminal side takes place in an anticlockwise direction and for a negative angle, the rotation takes place in a clockwise direction is the correct answer.
In this question,
An angle is formed when two straight lines or rays meet at a common endpoint. The measure of the 'opening' between these two rays is called an 'angle'. The common point of contact is called the vertex of an angle.
When measuring the angle, one arm is fixed as the base while the other moves clockwise or counterclockwise to form an angle between the two. Rotation is measured from the initial side to the terminal side of the angle.
The amount of rotation of a ray from its initial position to final position in anticlockwise direction is called positive angle. An angle generated in a clockwise direction from the base is a negative angle.
Hence we can conclude that for a positive angle, the rotation from the initial side to the terminal side takes place in an anticlockwise direction and for a negative angle, the rotation takes place in a clockwise direction is the correct answer.
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Answer:
b. no autocorrelation.
Step-by-step explanation:
The Durbin-Watson test assumes that
H0:ρ=0
HA:ρ≠0
p=0 is a statement for the null hypothesis that assumes that the error term in one period is not correlated to the error term in the previous period.
The Durbin-Watson test is used in regression analysis to test for autocorrelation. The results from the test would always range from 0 to 4. A value of less than 2.0 indicates positive autocorrelation. A value of 2.0 indicates no autocorrelation, and a value of 2.0 to 4.0 indicates negative autocorrelation.
This equation uses two properties of logarithms:


So you could take the ln from left and right hand side in the equation, and get:
(2-x)ln 3 = x ln 5
then
2 ln 3 - x ln 3 - x ln 5 = 0 =>
x(ln 3 + ln 5) = 2 ln 3
so x = 2 ln 3 / (ln3 + ln5)
Now using the 1st property you can say 2 ln 3 is ln 3² = ln9
and using the 2nd property you can say ln3 + ln5 = ln15
so x= ln9 / ln15