Question

Find the slope of the line that is parallel to the line with equation 3x + 4y = 10.

Answer 1

Answer:

$slope = m =\frac{-3}{4}$

Step-by-step explanation:

The equation of a line in  slope-intercept form  is.

$y = mx + b$----->(eq 1)  

∴ m is slope

$3x + 4y = 10$

subtract 3x from both sides.

 $3x - 3x + 4y = -3x + 10$

 $4y = -3x + 10$

divide 4 on both sides

$\frac{4y}{4} = \frac{-3x + 10}{4}$

$y = \frac{-3x}{4} + \frac{10}{4}$

$y = \frac{-3}{4}x + \frac{10}{4}$  ----->(eq 2)  

By comparing (eq 1) and (eq 2)  

$slope = m =\frac{-3}{4}$