Answer:
sqrt166, 13, 14
Step-by-step explanation:
----------------------------------------------------------------------------------------------
Find the duration
----------------------------------------------------------------------------------------------
Time : 9:00am to 10:15am
Duration: 1hour 15 mins or 1.25hours
----------------------------------------------------------------------------------------------
Find difference in distance travelled between the two cyclists.
----------------------------------------------------------------------------------------------
Difference in speed = 6km/h
1 hour = 6 km
1.25 hours = 7.5km
----------------------------------------------------------------------------------------------
Find the distance the cyclist traveled
----------------------------------------------------------------------------------------------
42.5 - 7.5 = 35km
35km ÷ 2 = 17.5km
The slower cyclist traveled 17.5 km in the 1.25 hours
17.5 + 7.5 = 25 km
The faster cyclist traveled 25km in the 1.25 hours
----------------------------------------------------------------------------------------------
Find the speed of the slower cyclist
----------------------------------------------------------------------------------------------
1.25 hour = 17.5 km
1 hour = 17.25 ÷ 1.25
1 hour = 14km
The cyclist was traveling at 14km/h
----------------------------------------------------------------------------------------------
Find the speed of the faster cyclist
----------------------------------------------------------------------------------------------
1.25 hour = 25km
1 hour = 25 ÷ 1.25
1hour = 20 km
The cyclist was traveling at 20km/hour
----------------------------------------------------------------------------------------------
Answer: The speed were 14km/h and 20 km/h
----------------------------------------------------------------------------------------------
These are just a few of the things you will learn in 6th grade. You will learn how to write a two- variable equation, how to identify the graph of an equation, graphing two-variable equations. how to interpret a graph and a word problem, and how to write an equation from a graph using a table, two-dimensional figures,Identify and classify polygons, Measure and classify angles,Estimate angle measurements, Classify triangles, Identify trapezoids, Classify quadrilaterals, Graph triangles and quadrilaterals, Find missing angles in triangles, and a lot more subjects. <span><span><span>Find missing angles in quadrilaterals
</span><span>Sums of angles in polygons
</span><span>Lines, line segments, and rays
</span><span>Name angles
</span><span>Complementary and supplementary angles
</span><span>Transversal of parallel lines
</span><span>Find lengths and measures of bisected line segments and angles
</span><span>Parts of a circle
</span><span>Central angles of circles</span></span>Symmetry and transformations
<span><span>Symmetry
</span><span>Reflection, rotation, and translation
</span><span>Translations: graph the image
</span><span>Reflections: graph the image
</span><span>Rotations: graph the image
</span><span>Similar and congruent figures
</span><span>Find side lengths of similar figures</span></span>Three-dimensional figures
<span><span>Identify polyhedra
</span><span>Which figure is being described
</span><span>Nets of three-dimensional figures
</span><span>Front, side, and top view</span></span>Geometric measurement
<span><span>Perimeter
</span><span>Area of rectangles and squares
</span><span>Area of triangles
</span><span>Area of parallelograms and trapezoids
</span><span>Area of quadrilaterals
</span><span>Area of compound figures
</span><span>Area between two rectangles
</span><span>Area between two triangles
</span><span>Rectangles: relationship between perimeter and area
</span><span>compare area and perimeter of two figures
</span><span>Circles: calculate area, circumference, radius, and diameter
</span><span>Circles: word problems
</span><span>Area between two circles
</span><span>Volume of cubes and rectangular prisms
</span><span>Surface area of cubes and rectangular prisms
</span><span>Volume and surface area of triangular prisms
</span><span>Volume and surface area of cylinders
</span><span>Relate volume and surface area
</span><span>Semicircles: calculate area, perimeter, radius, and diameter
</span><span>Quarter circles: calculate area, perimeter, and radius
</span><span>Area of compound figures with triangles, semicircles, and quarter circles</span></span>Data and graphs
<span><span>Interpret pictographs
</span><span>Create pictographs
</span><span>Interpret line plots
</span><span>Create line plots
</span><span>Create and interpret line plots with fractions
</span><span>Create frequency tables
</span><span>Interpret bar graphs
</span><span>Create bar graphs
</span><span>Interpret double bar graphs</span><span>
</span></span><span>
</span></span>
Two equations with infinite solutions would look the exact same. Example:
y=mx+b
y=mx+b
Example 2
y=2x+5
y=2x+5
For an equation with no solution they would have the same slope but different y intercepts. An equation with same slope and same y intercepts would have infinite solutions.
Answer:
i dont know 3&4 but #5 is B
Step-by-step explanation: