The formula for the cost of buying a car is:

Mathematics

1 answer:

sleet_krkn [62]3 years ago

6 0

Answer: £6200

Step-by-step explanation:

Given the formula for cost of a car = 12 x monthly payment + deposit,

where monthly payment = £350 and deposit = £2000

Insert the values into the formula:

Cost of the car= 12 (£350) + £2000

Multiply 12 by £350, then add £2000

= 12 x £350 + £2000

£4200 + £2000

=£6200

Therefore, Cost of the car is £6200

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Mr. Wilson opened a bakery and a juice bar in his neighborhood. The functions below represent the profit, in dollars, earned fro

zavuch27 [327]

Answer:

The answer is given below

Step-by-step explanation:

The question is not complete, because the function for the profit is not given but I can show you how to calculate this.

Since Mr. Wilson has a bakery and a juice bar, his total profit earned in t months would be the sum of profit from the bakery with the profit from the juice bar within t months.

Let us assume that the profit from the bakery in t months is given by:

B(t) = 2t³

while the profit from the juice bar in t months is given by:

J(t) = $2.3^t-2$

Therefore the total profit is given by:

P(t) = B(t) - J(t) = $2t^3+2.3^t-2$

4 0

4 years ago

Find k given that these three points are collinear.<br> A(0, -2), B(2, 0), and C(5, k)

goldfiish [28.3K]

Answer:

k = 3.

Step-by-step explanation:

If they are collinear the slope of AB = the slope of BC, so :-

(0- (-2)) / (2 - 0) = (k - 0) / (5 - 2)

2/2 = k/3

1 = k/3

k = 3.

7 0

3 years ago

Hi, can somoene please check why my solution and explain why I get the wrong answer.

trapecia [35]

Answer:

$a_n=(1-n)2^n+3^n$

Step-by-step explanation:

You are correct down to the part where you add the partial results:

$a_n=a_n^h+a_n^p=A3^n+B2^n-n2^n\\\text{Using the given starter values, we can find A, B:}\\a_0=2=A\\a_1=7=3A+2B+2\\\text{has solution A=1, B=1, so ...}\\\\a_n=3^n+2^n-n2^n$