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4 years ago

Over 5 straight plays a football team gained 8 yards lost 4 yards

1 answer:

4 0

Over 10 straight plays they would have 16 gained years and 8 lost yards. over 20 straight plays the would have 32 yards gained and 16 lost yards. what you do to find out how to do this is dividing the yards gained and the yards lost and then multiplying all the numbers by the number you got.

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The scale of a certain map is 4/5 inch = 16 miles. A square park is represneted on the map by a square with side length 5/8 inch

lions [1.4K]

Answer:

The area of this park is 130.60 square miles.

Step-by-step explanation:

Given : The scale of a certain map is $\frac{4}{5}$ inch = 16 miles. A square park is represented on the map by a square with side length $\frac{5}{8}$ inch.

To find : What is the actual area of this park?

Solution :

The scale of a certain map is $\frac{4}{5}$ inch = 16 miles.

Let the side length of $\frac{5}{8}$ inch = x miles.

So, $\dfrac{\frac{4}{5}}{\frac{5}{8}}=\dfrac{16}{x}$

$\dfrac{4\times 8}{5\times5}=\dfrac{16}{x}$

$\dfrac{32}{25}=\dfrac{16}{x}$

$x=\dfrac{16\times 25}{35}$

$x=11.428$

The side length of a square is 11.428 miles.

The area of the square is $A=s^2$ .

$A=(11.42)^2$

$A=130.599\ miles^2$

To nearest hundredth,

The area of this park is 130.60 square miles.

8 0

4 years ago

The smaller triangle is dilated to create the larger triangle. The center of

blagie [28]

To create a larger plot you need to dilation it

6 0

3 years ago

Please show the working and answer. you can take a picture for the working.

baherus [9]

Answer:

(a) The area of the triangle is approximately 39.0223 cm²

(b) ∠SQR is approximately 55.582°

Step-by-step explanation:

(a) By sin rule, we have;

SQ/(sin(∠SPQ)) = PQ/(sin(∠PSQ)), which gives;

5.4/(sin(52°)) = 6.8/(sin(∠PSQ))

∴ (sin(∠PSQ)) = (6.8/5.4) × (sin(52°)) ≈ 0.9923

∠PSQ = sin⁻¹(0.9923) ≈ 82.88976°

Similarly, we have;

5.4/(sin(52°)) = SP/(sin(180 - 52 - 82.88976))

Where, 180 - 52 - 82.88976 = ∠PQS = 45.11024

SP = 5.4/(sin(52°))×(sin(180 - 52 - 82.88976)) ≈ 4.8549

Given that RS : SP = 2 : 1, we have;

RS = 2 × SP = 2 × 4.8549 ≈ 9.7098

We have by cosine rule, $\overline {RQ}$ ² = $\overline {SQ}$ ² + $\overline {SR}$ ² - 2 × $\overline {SQ}$ × $\overline {SR}$ × cos(∠QSR)

∠QSR and ∠PSQ are supplementary angles, therefore;

∠QSR = 180° - ∠PSQ = 180° - 82.88976° = 97.11024°

∠QSR = 97.11024°

Therefore;

$\overline {RQ}$ ² = 5.4² + 9.7098² - 2 × 5.4×9.7098× cos(97.11024)

$\overline {RQ}$ ² ≈ 136.42

$\overline {RQ}$ = √(136.42) ≈ 11.6799

The area of the triangle = 1/2 × $\overline {PQ}$ × $\overline {PR}$ × sin(∠SPQ)

By substituting the values, we have;

1/2 × $\overline {PQ}$ × $\overline {PR}$ × sin(∠SPQ)

1/2 × 6.8 × (4.8549 + 9.7098) × sin(52°) ≈ 39.0223 cm²

The area of the triangle ≈ 39.0223 cm²

(b) By sin rule, we have;

$\overline {RS}$ /(sin(∠SQR)) = $\overline {RQ}$ /(sin(∠QSR))

By substituting, we have;

9.7098/(sin(∠SQR)) = 11.6799/(sin(97.11024))

sin(∠SQR) = 9.7098/(11.6799/(sin(97.11024))) ≈ 0.82493

∠SQR = sin⁻¹(0.82493) ≈ 55.582°.

8 0

3 years ago

una ventana rectangular tiene l metros de ancho y h metros de altura, con un perímetro de 6 metros y un área de 2m² ¿cuál es la

seropon [69]

Answer:

The formula for calculating the width of the window is

$w=\frac{-(-3)(+/-)\sqrt{-3^{2}-4(1)(2)}} {2(1)}$

Step-by-step explanation:

<u><em>The question in English is</em></u>

A rectangular window is l meters wide and h meters high, with a perimeter of 6 meters and an area of 2m². What is the formula for calculating the width of the window?

we know that

The perimeter of the window is equal to

$P=2(l+w)$