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Ugo [173]
3 years ago
9

Compete the square to determine minum or maxuim value of function define by -x2+10x+5

Mathematics
1 answer:
HACTEHA [7]3 years ago
3 0

Answer:

maximum value y = 30

Step-by-step explanation:

Given

- x² + 10x + 5

To complete the square the coefficient of the x² term must be 1

factor out - 1

= - (x² - 10x) + 5

To complete the square

add/subtract ( half the coefficient of the x- term )² to x² - 10x

= - (x² + 2(- 5)x + 25 - 25) + 5

= - (x - 5)² + 25 + 5

= - (x - 5)² + 30 ← in vertex form

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Hence vertex = (5, 30)

The max/ min occurs at the vertex

Since a < 0 then vertex is a maximum

Hence maximum value is y = 30

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Answer:

<em>8 C sometimes</em>

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Step-by-step explanation:

<u>Algebraic Operations </u>

Some basic rules must be fresh in our minds when trying to simplify complex algebraic expressions. For example, the power rule respect to the product or quotient:

\displaystyle \left(\frac{x^n.y^m}{z^p}\right)^q= \frac{x^{qn}.y^{qm}}{z^{qp}}

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Let's face the questions at hand

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Now we pick

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<em>Answer: C sometimes </em>

9 simplify(4xy^2)^3(xy)^5

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=64x^3y^6x^5y^5

=64x^8y^{11}

10 simplify(2t^-3)^3(0.4r)^2

(2t^{-3})^3(0.4r)^2=2^3(t^{-3})^30.4^2r^2

=8t^{-9} 0.16 r^2

=1.28t^{-9} r^2

\displaystyle \frac{1.28 r^2}{t^9}

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