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Triss [41]
4 years ago
15

NEED HELP ASAP!!! DUE BY 5

Mathematics
1 answer:
Paraphin [41]4 years ago
5 0

Answer:

86m^2

Step-by-step explanation:

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Alexandra [31]
(1/4)x + 8 = 16

or...
(x/4) + 8 = 16
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4 years ago
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Find the unknown. 531 = ( × 6) + 21
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The answer would be x = 85
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A sample of a radioactive isotope had an initial mass of 360 mg in the year 1998 and
RUDIKE [14]

Answer:

193 mg

Step-by-step explanation:

Exponential decay formula:

  • A_t = A_0e^r^t
  • where Aₜ = mass at time t, A₀ = mass at time 0,  r = decay constant (rate), t = time  

Our known variables are:

  • 1998 to the year 2004 is a total of t = 6 years.
  • The sample of radioactive isotope has an initial mass of A₀ = 360 mg at time 0 and a mass of Aₜ = 270 mg at time t.

Let's solve for the decay constant of this sample.

  • 270=360e^-^r^(^6^)
  • 270=360e^-^6^r
  • \frac{3}{4} =e^-^6^r
  • \text{ln} (\frac{3}{4} )= \text{ln}(e^-^6^r)
  • \text{ln} (\frac{3}{4} )=-6r
  • r=-\frac{\text{ln}\frac{3}{4} }{6}
  • r=0.04794701

Using our new variables, we can now solve for Aₜ at t = 7 years, since we go from 2004 to 2011.

Our new initial mass is A₀ = 270 mg. We solved for the decay constant, r = 0.04794701.

  • A_t=270e^-^(^0^.^0^4^7^9^4^8^0^1^)^(^7^)
  • A_t=270e^-^0^.^3^3^5^6^2^9^0^7
  • A_t=193.01982213

The expected mass of the sample in the year 2011 would be 193 mg.

3 0
3 years ago
Evaluate the following algebraic expressions by substituting z raised to the second power where z=7
PIT_PIT [208]

Answer:

49

Step-by-step explanation:

z=7 which means that 7 raised to the second power is 7 multiplied by itself. When you do 7 x 7 your answer will be 49. Hope that helps :)

3 0
3 years ago
Two less than 2 times a number is the same as the number plus 64. What is the number?
Alex Ar [27]
Set it up as an equation. "A number" is x.

2x-2=x+64

Move all of the x terms to one side by subtracting x from both sides, then add 2 to both sides to isolate x.

X=66

The number is 66
8 0
3 years ago
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