Answer:
Hello your question is poorly written attached below is the complete question
answer : attached below
Step-by-step explanation:
To Prove: Z is located 2/3 of the distance from each vertex of ΔABC to the midpoint of the opposite side. we will apply ; property of bisecting a line , equality theorem , transitive property and similarity theorem
Attached below is the proof
The question isn’t clear, can you write it better so I can understand?
Because ΔQRS is congruent to <span>ΔTUV, the the segments GS and TV are also congruent due to the letter order (Q and T are first and S and V are 3rd.) Since they are congruent QS=TV. So 3v + 2 = 7v - 6
</span><span>
</span><span>Work:
</span>3v + 2 = 7v - 6
+6 +6
3v + 8=7v
-3v -3v
<u>8</u> = <span><u>4v</u>
</span>4 4
2 = v
3(2) + 2 = GS
6+2 = GS
8 = GS
7(2) - 6 = TV
14-6=TV
8 = TV
Final Answer: 8=QS and 8=TV
The equation of an ellipse is x²/a² + y²/b² =1
a being the distance between the center & x intercept =7
b being the distance between the center & y intercept =5
Hence the equation of this ellipse is:
x²/49 + y²/25 =1
