Z = 25. y = 101. I got this because of the parallel lines theorem. In essence, what this theorem means is that the alternate exterior angles are congruent. If you see, this means that 6z - 71 = 79. After solving this equation, you get z = 25. y = 101 because of supplementary angles. Z is 25, but the value of that angle is not 25 because first, you have to solve the equation, in which you get 79. 180 - 79 = 101.
Z = 25.
Y = 101.
Same as before, if we take 368 to be the 100%, how much is 20% off that?
so, the discount is that much, thus, the discounted price is then 368 - d.
Post war means the time after a war had just taken place
Problem 1
<h3>Answer: 7/10</h3>
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Explanation:
The formula we'll use is
P(A or B) = P(A) + P(B)
which only works if A and B are mutually exclusive events.
P(A or B) = P(A) + P(B)
P(A or B) = 7/20 + 7/20
P(A or B) = (7+7)/20
P(A or B) = 14/20
P(A or B) = (7*2)/(10*2)
P(A or B) = 7/10
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Problem 2
<h3>Answer: 3/4</h3>
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Explanation:
We'll use the same formula as the previous problem.
P(A or B) = P(A) + P(B)
P(A or B) = 3/10 + 9/20
P(A or B) = 6/20 + 9/20
P(A or B) = (6+9)/20
P(A or B) = 15/20
P(A or B) = (3*5)/(4*5)
P(A or B) = 3/4
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Problem 3
<h3>Answer: 3/5</h3>
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Explanation:
We'll use the same formula as the previous problem.
P(A or B) = P(A) + P(B)
P(A or B) = 7/20 + 1/4
P(A or B) = 7/20 + 5/20
P(A or B) = (7+5)/20
P(A or B) = 12/20
P(A or B) = (4*3)/(4*5)
P(A or B) = 3/5
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Problem 4
<h3>Answer: 0</h3>
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Explanation:
This time we're asked to find P(A and B), but since the two events are mutually exclusive, this means the probability of both occurring is 0.
Mutually exclusive events cannot happen simultaneously.
An example would be flipping heads and tails at the same time on the same coin.
The info about P(A) and P(B) is not relevant.
