I believe it would be (-4, 8); because when x = -4, y = f(x) = 8.
Answer:
x≠-1,1
Step-by-step explanation:
f(g(x)) is a composition where g(x) is is substituted for x in f(x).
Recall, f(x) is 2/x. So we write 2/|x|-1. This places x in the denominator and 0 cannot be in the denominator x. Any value of x that makes the denominator 0 will not be in the domain.
|x|-1=0
|x|=1
x=1,-1
A.Yes a function as a vertical line crosses the curve at one point only.
B.the domain is [-4,3]
C. the range is [-3,3]
D. it's -3
Answer:
2x^3−7x^2+16x−15
Step-by-step explanation:
(2x−3)(x^2−2x+5)
=(2x+−3)(x^2+−2x+5)
=(2x)(x^2)+(2x)(−2x)+(2x)(5)+(−3)(x^2)+(−3)(−2x)+(−3)(5)
=2x^3−4x^2+10x−3x^2+6x−15
=2x3−7x2+16x−15
Answer:
Step-by-step explanation:
