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3 years ago

11

The direction of mixing an insect spray to use 2 7/8 ounces of chemical in each gallon of water. How many ounces of chemical sho

uld be mixed with 6 1/3 gallons of water? First estimate the answer to the application problem. Then find the exact answer.

1 answer:

Gwar [14]3 years ago

7 0

Need approx 3 oz chemical to 1 gal water.
Conversion factor is then approx. 3 oz
---------
1 gal

Mult this result by 6 gal. This gives you 18 oz, approx.

Now let's look for a more exact solution:

2.75 oz 19 gal
---------- * ---------- = 17.4 oz. The 18 oz estimate was close.
1 gal 3

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The volume of a cube is V= S^3 where V is the volume and s is the length of one side what is the volume of a cube if the length

sammy [17]

The volume of cube is 1000 cubic feet

<em><u>Solution:</u></em>

Given that,

<em><u>The volume of cube is given by formula:</u></em>

$V = s^3$

Where,

V is the volume of cube

"s" is the length of one side

<em><u>What is the volume of a cube if the length of a side s is 10 feet</u></em>

Given, s = 10 feet

<em><u>Substitute s = 10 in given formula,</u></em>

$V = 10^3\\\\V = 10 \times 10 \times 10\\\\V = 1000$

Thus volume of cube is 1000 cubic feet

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3 years ago

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Answer:

see explanation

Step-by-step explanation:

sinΘ is only valid for values in the interval

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sinΘ = $\frac{5}{2}$ is outwith this interval and is not valid

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3 years ago

In circle G with m \angle FGH= 86m∠FGH=86 and FG=16FG=16 units, find the length of arc FH. Round to the nearest hundredth.

Igoryamba

Answer:

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Step-by-step explanation:

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2 years ago

Roll the number cube to find the observed frequency. Which statements are true? Check all that apply

ch4aika [34]

Answer:

(a) and (c)

Step-by-step explanation:

Given

See attachment for complete question

Required

Select all true statements

First, calculate the total observed frequency;

$Total = 11 + 16 + 14 + 20 + 12 + 17$

$Total = 90$

<u>(a): Relative frequency of 4 is 2/9</u>

Relative frequency is calculated by:

$RF= \frac{Observed\ Frequency}{Total}$

For roll 4

$Observed\ frequency = 20$

So, the relative frequency is:

$RF = \frac{20}{90}$

Simplify

$RF = \frac{2}{9}$

<em>(a) is true</em>

<u>(b): Experimental probability of 3 greater than its theoretical probability</u>

The experimental probability is its relative frequency;

For roll 3

$Observed\ frequency = 14$

The experimental probability is:

$Pr = \frac{14}{90}$

Simplify

$Pr = \frac{7}{45} = 0.156$

To calculate the theoretical probability, w have:

$S = \{1,2,3,4,5,6\}$ ---- sample space

$n(S)= 6$

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The theoretical probability is:

$Pr = \frac{1}{6} = 0.167$

The theoretical probability is $greater\ than\ the$ experimental probability.

<em>(b) is false</em>

<u>(c): Experimental probability of 2 greater than its theoretical probability</u>

Using the explanations in (b), we have:

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$Observed\ frequency = 16$

The experimental probability is:

$Pr = \frac{16}{90}$

Simplify

$Pr = \frac{8}{45} = 0.178$

To calculate the theoretical probability, we have:

$n(S)= 6$

$n(2) = 1$

The theoretical probability is:

$Pr = \frac{1}{6} = 0.167$

The experimental probability is $greater\ than\ the$ theoretical probability.

<em>(c) is true</em>

<u>(d): Relative frequency of 5 is 2/13</u>

For roll 5

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The relative frequency is:

$RF = \frac{12}{90}$

Simplify

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<em>(d) is true</em>

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3 years ago

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crimeas [40]

Answer:

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Step-by-step explanation:

a=l×w

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