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2 years ago

The area of a right triangle is 36 square

Mathematics

2 answers:

sertanlavr [38]2 years ago

4 0

Answer:

6 m

Step-by-step explanation:

36 m^2 = bh/2

36·2 = bh/2·2

72 = bh

72 = 12·6

check

36 m^2 = 12·6/2

36 = 36

stepan [7]2 years ago

3 0

Base is 12 and height is 24

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analyze the diagram below and complete the instructions that follow . find the value of z. A.11 B.32 C.50 D.68

masha68 [24]

Answer:

Step-by-step explanation:

x = √30² - 18² = √576 = 24

tan A = 18/24 = 3/4

∠A = ∠B

tan B = tan A = 24 / y = 3 / 4

y = (24 x 4) / 3 = 32

Z = y + 18 = 32 + 18 = 50

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2 years ago

The diameter of a circle is 9 cm. Find its area to the nearest tenth.

Alja [10]

Cut diameter in half to find radius

9/2 = 4.5

radius = 4.5

This is the formula for area of a circle:

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pi * 4.5^2

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Answer:

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2 years ago

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A college student completed some courses worth 3 credits and some courses worth 4 credits. The student earned a total of 59 cred

DedPeter [7]

Answer:

They completed 13, 3 credit classes

Step-by-step explanation:

1. Make 2 formulas. In this case: x+y=18

and 3x+4y=59

2. Then multiply x+y=18 by 3 and subtract the two equations.

Find y which is 5 and input into the equations. Then find your answer.

5 0

3 years ago

Water is drained out of tank, shaped as an inverted right circular cone that has a radius of 4cm and a height of 16cm, at the ra

bearhunter [10]

Answer:

$\frac{dh}{dt}=-\frac{1}{2\pi}cm/min$

Step-by-step explanation:

From similar triangles, see diagram in attachment

$\frac{r}{4}=\frac{h}{16}$

We solve for $r$ to obtain,

$r=\frac{h}{4}$

The formula for calculating the volume of a cone is

$V=\frac{1}{3}\pi r^2h$

We substitute the value of $r=\frac{h}{4}$ to obtain,

$V=\frac{1}{3}\pi (\frac{h}{4})^2h$

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$V=\frac{1}{48}\pi h^3$

We now differentiate both sides with respect to $t$ to get,

$\frac{dV}{dt}=\frac{\pi}{16}h^2 \frac{dh}{dt}$

We were given that water is drained out of the tank at a rate of $2cm^3/min$

This implies that $\frac{dV}{dt}=-2cm^3/min$ .

Since we want to determine the rate at which the depth of the water is changing at the instance when the water in the tank is 8cm deep, it means $h=8cm$ .

We substitute this values to obtain,

$-2=\frac{\pi}{16}(8)^2 \frac{dh}{dt}$

$\Rightarrow -2=4\pi \frac{dh}{dt}$

$\Rightarrow -1=2\pi \frac{dh}{dt}$

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3 years ago

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marin [14]

Answer:140 over 3

Step-by-step explanation: i got that answer but i dont think its the right

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3 years ago