When you calculate that all up you get 212 <span />
Answer:
Angle A = Angle X
Line Segment CA = Line Segment ZX
Angle Y = Angle B
Line Segment YX = Line Segment BA
Step-by-step explanation:
Both triangles are stated to be equal so we can draw two triangles and label them. One triangle has Point A, Point B, and Point C. The second triangle has Point X, Point Y, and Point Z. Make sure that Point X on the second triangle is in the same spot as Point A on the first triangle (same for points B, C, Y, and Z).
Answer:
64.6 km/h
Step-by-step explanation:
18:14 = 18h 14'
1h = 60'
18h = 17h + 60'
18h14' = 17h + 60' ´14' = 17h 74'
then:
17h 74'
-17h 22'
= 0h 52'
the train travelled 56km at 52 minutes
56km/52minutes
1 hour = 60 minutes
52 minutes = 52/60 = 0.86667 hours
then:
56km/52minutes = 56km/0.86667hours
= 64.615 km/hours
Answer:

![\sqrt[3]{0.95} \approx 0.9833](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B0.95%7D%20%5Capprox%200.9833)
![\sqrt[3]{1.1} \approx 1.0333](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1.1%7D%20%5Capprox%201.0333)
Step-by-step explanation:
Given the function: ![g(x)=\sqrt[3]{1+x}](https://tex.z-dn.net/?f=g%28x%29%3D%5Csqrt%5B3%5D%7B1%2Bx%7D)
We are to determine the linear approximation of the function g(x) at a = 0.
Linear Approximating Polynomial,
a=0
![g(0)=\sqrt[3]{1+0}=1](https://tex.z-dn.net/?f=g%280%29%3D%5Csqrt%5B3%5D%7B1%2B0%7D%3D1)

Therefore:

(b)![\sqrt[3]{0.95}= \sqrt[3]{1-0.05}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B0.95%7D%3D%20%5Csqrt%5B3%5D%7B1-0.05%7D)
When x = - 0.05

![\sqrt[3]{0.95} \approx 0.9833](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B0.95%7D%20%5Capprox%200.9833)
(c)
(b)![\sqrt[3]{1.1}= \sqrt[3]{1+0.1}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1.1%7D%3D%20%5Csqrt%5B3%5D%7B1%2B0.1%7D)
When x = 0.1

![\sqrt[3]{1.1} \approx 1.0333](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1.1%7D%20%5Capprox%201.0333)
X=3.93 in.
hope this helps you ♥