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bezimeni [28]
3 years ago
11

What is 3 x -2? Please answer quickly!!!

Mathematics
1 answer:
Ket [755]3 years ago
4 0

Answer: -6

Step-by-step explanation:

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Three randomly selected households are surveyed. The numbers of people in the households are 3​, 5​, and 10. Assume that samples
nalin [4]

Answer:

there is no anwser

Step-by-step explanation:

im lazy

4 0
3 years ago
8TH GRADE MATH 100 POINTS+BRAINLIEST - Factor Quadratic equations- please write out the steps, explain simply, and possibly prov
Anestetic [448]

Hello,

We have : (a + b)² = a² + 2ab + b²

4x² + 20x + 25 = (2x)² + 2 × 2x × 5 + 5² = (2x + 5)² → answer B

Here, we have a = 2x and b = 5 !

6 0
2 years ago
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Suppose a research firm conducted a survey to determine the mean amount steady smokers spend on cigarettes during a week. A samp
shutvik [7]

Answer:

0.9910 = 99.10% probability that a sample of 170 steady smokers spend between $19 and $21

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 20, standard deviation of 5:

This means that \mu = 20, \sigma = 5

Sample of 170:

This means that n = 170, s = \frac{5}{\sqrt{170}}

What is the probability that a sample of 170 steady smokers spend between $19 and $21?

This is the p-value of Z when X = 21 subtracted by the p-value of Z when X = 19.

X = 21

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{21 - 20}{\frac{5}{\sqrt{170}}}

Z = 2.61

Z = 2.61 has a p-value of 0.9955

X = 19

Z = \frac{X - \mu}{s}

Z = \frac{19 - 20}{\frac{5}{\sqrt{170}}}

Z = -2.61

Z = -2.61 has a p-value of 0.0045

0.9955 - 0.0045 = 0.9910

0.9910 = 99.10% probability that a sample of 170 steady smokers spend between $19 and $21

3 0
3 years ago
Find the quotient: –3.5 and –0.875<br> –40<br> –4<br> 4<br> 40
JulijaS [17]

Answer: its 4

Step-by-step explanation: i took the quiz just now

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3 years ago
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What is one benefit and one limitation of loss aversion
Eddi Din [679]

Answer:

"...loss aversion refers to people's tendency to prefer avoiding losses to acquiring equivalent gains: it is better to not lose $5 than to find $5."

7 0
3 years ago
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