I think it is d if not then im sorry
Answer:
vcannon = 11.42 [m/s]
Explanation:
To solve this problem we must use the principle of conservation of linear momentum which tells us that the momentum of the cannon ball is conserved before and after shooting.
This is at the time of the shot we have two movements, that of the cannon ball moving to the East, while the cannon moves to the left due to the reaction caused by the explosion.
where:
mcannon = mass of the cannon = 700 [kg]
vcannon = velocity of the cannon [m/s]
mcannonball = 20 [kg]
vcannonball = 400 [m/s]
Now replacing:
<h2>
Answer: approx. 1.625 m/s²</h2>
<h3>
Explanation:</h3>
The acceleration due to gravity on the surface of the Moon is approximately 1.625 m/s².
Compare that to the surface of the earth which is approximately 9.8 m/s². That makes the acceleration on the moon about 16.6% that on Earth's surface.
Answer:
Explanation:
1 ) Let the initial horizontal velocity of car be v .
For vertical displacement
vertical displacement h = 21.3 - 2.3 = 19 m
Time taken to fall by 19 m be t
19 = 1/2 x 9.8 t² ( initial downward velocity is zero )
t = 1.97 s
This is also the time taken to cover horizontal displacement of 54 m which is width of river .
horizontal speed v = 54 / 1.97 m /s
v = 27.41 m /s
2 )
At the time of landing on other side , car will have both vertical and horizontal speed .
vertical speed
v = u + gt
= 0 + 9.8 x 1.97 = 19.31 m /s
horizontal speed will remain same as the initial speed = 27.41 m /s
Resultant speed = √ ( 27.41² + 19.31² )
= √ ( 751.3 + 372.87)
= 33.52 m /s