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svetoff [14.1K]
3 years ago
15

6. Mithra is an unknown planet that has two airless moons. A and B, in circular orbits around it.

Physics
1 answer:
Ainat [17]3 years ago
4 0

The acceleration of gravity on Moon B is D) 0.25 m/s2

Explanation:

The data listed in the problem are not clear: find them in the table attached.

The acceleration of gravity on a planet is given by the following equation:

g=\frac{GM}{R^2}

where:

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2} is the gravitational constant

M is the mass of the planet

R is the radius of the planet

Here we want to find the acceleration of gravity on the surface of Moon B, which has the following data:

M=1.5\cdot 10^{20} kg (mass)

R=2.0\cdot 10^5 m (radius)

And substituting into the equation, we find:

g=\frac{(6.67\cdot 10^{-11})(1.5\cdot 10^{20})}{(2.0\cdot 10^5)^2}=0.25 m/s^2

Learn more about gravity:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

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Why it is easier to lift a small stone but harder to lift heavy one on the surface of Earth​
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Answer:

since small stone has less mass so the gravitational pull of the earth is lesser in case of this but this is not for the bigger stone as the gravitational pull of the earth is greater...

PLEASE MARK BRAINLIEST!!!!!

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3 years ago
Humans can see several thousand shades of color but have cone photoreceptors that are sensitive to only three (perhaps four) wav
kipiarov [429]

Answer:

B. Color perception is achieved by activation of various combinations between the tree cone types.

Explanation:

Human eye have only three photo receptor ( three wavelength) but they can see several thousands of shades of color because color perception is gained by combination of these three wave length cone types ( RED, BLUE AND GREEN) into various combinations. Our retina have two types of cell:- cone cells and cylindrical cells. Cone cells are responsible for the identification of color.

4 0
3 years ago
what nuclear fission and nuclear fusion have in common? A. They’re both used in power plants B. they have less mass than their r
arsen [322]

A. They’re both used in power plants . . . No.  

Nuclear fission is used in <u>all</u> nuclear power plants.  Fusion isn't used in <u>any</u> power plants yet, because we can't control it safely enough yet.  The only thing we can use nuclear fusion for is still bombs.

B. they have less mass than their reactants . . . No.  

Fission involves breaking atoms into pieces. Its products have less mass than its raw materials.  Fusion involves sticking atoms together to make new ones.  Its products have more mass than its raw materials.  Whatever the incomplete statement ' B ' is trying to say, it's not true of both processes.

<em>B. ==> </em> If you try really hard, this statement <em>(B)</em> can be undertood as true.  The TOTAL MASS after both a fission reaction and a fusion reaction is less than the total mass of whatever was fissled or fuzled.  In both cases, the missing mass is accounted for by the energy that was radiated from the site of the nuclear reaction.

But the statement in ' B ' is very poorly written.  When you read it, you don't know what 'they' refers to.  

C. they start with the same reactants . . . No.  

Man-made fission starts with the heaviest atoms ... Uranium and Plutonium.  Man-made fusion starts with the lightest atoms ... Hydrogen.

D. their products have more mass than their reactants ... No.

Fission breaks heavy atoms and makes lighter ones.  Fusion glues light atoms and makes heavier ones.

Gee whiz !  <em>None of the choices is correct. </em>

7 0
3 years ago
Read 2 more answers
A 0.300 kg block is pressed against a spring with a spring constant of 8050 N/m until the spring is compressed by 6.00 cm. When
natita [175]

Answer:

a) \mu_{k} = 0.704, b) R = 0.312\,m

Explanation:

a) The minimum coeffcient of friction is computed by the following expression derived from the Principle of Energy Conservation:

\frac{1}{2}\cdot k \cdot x^{2} = \mu_{k}\cdot m\cdot g \cdot \Delta s

\mu_{k} = \frac{k\cdot x^{2}}{2\cdot m\cdot g \cdot \Delta s}

\mu_{k} = \frac{\left(8050\,\frac{N}{m} \right)\cdot (0.06\,m)^{2}}{2\cdot (0.3\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot (7\,m)}

\mu_{k} = 0.704

b) The speed of the block is determined by using the Principle of Energy Conservation:

\frac{1}{2}\cdot k \cdot x^{2} = \frac{1}{2}\cdot m \cdot v^{2}

v = x\cdot \sqrt{\frac{k}{m} }

v = (0.06\,m)\cdot \sqrt{\frac{8050\,\frac{N}{m} }{0.3\,kg} }

v \approx 9.829\,\frac{m}{s}

The radius of the circular loop is:

\Sigma F_{r} = -90\,N -(0.3\,kg)\cdot (9.807\,\frac{m}{s^{2}} ) = -(0.3\,kg)\cdot \frac{v^{2}}{R}

\frac{\left(9.829\,\frac{m}{s}\right)^{2}}{R} = 309.807\,\frac{m}{s^{2}}

R = 0.312\,m

5 0
4 years ago
If a sound wave travels through air at a speed of 345 m/s, what would be the frequency of a 0.80 m long wave?
den301095 [7]

Answer:

D

Explanation:431.3

7 0
3 years ago
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