The acceleration of gravity on Moon B is D) 0.25 m/s2
Explanation:
The data listed in the problem are not clear: find them in the table attached.
The acceleration of gravity on a planet is given by the following equation:
where:
is the gravitational constant
M is the mass of the planet
R is the radius of the planet
Here we want to find the acceleration of gravity on the surface of Moon B, which has the following data:
(mass)
(radius)
And substituting into the equation, we find:
Learn more about gravity:
#LearnwithBrainly
Answer:
The ratio is 9.95
Solution:
As per the question:
Amplitude,
Wavelength,
Now,
To calculate the ratio of the maximum particle speed to the speed of the wave:
For the maximum speed of the particle:
where
= angular speed of the particle
Thus
Now,
The wave speed is given by:
Now,
The ratio is given by:
Answer:
Explanation:
using the law of the conservation of the linear momentum:
where is the inicial momemtum and
is the final momentum
the linear momentum is calculated by the next equation
P = MV
where M is the mass and V is the velocity.
so:
where m is the mass of the proton and is the velocity of the proton after the collision,
is the mass of the nucleus and
is the velocity of the nucleus after the collision.
therefore, we can formulate the following equation:
m(270 m/s) = m + 14m
then, m is cancelated and we have:
270 = +
This is a elastic collision, so the kinetic energy K is conservated. Then:
and
Kf =
then,
=
here we can cancel the m and get:
=
now, we have two equations and two incognites:
270 = +
(eq. 1)
=
in the second equation, we have:
36450 = (eq. 2)
from this last equation we solve for as:
and replace in the other equation as:
270 = 14
so,
Vp is negative because the proton go in the -i hat direction.
Finally, replacing this value on eq. 1 we get: